Howie Hua
Region: US
Wednesday 28 December 2022 20:25:13 GMT
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De Vieze Man :
HOW EXCITING
2023-01-06 13:21:52
3
Eddie Price :
lovely video, Howie!
2022-12-29 16:29:21
1
AmongDream :
i knew it bc i tried something like this before multiple times and realized it's always the same but my method was different
2022-12-31 03:31:53
1
who? :
how to use logarithms in secret. love it!
2023-01-02 17:33:26
3
Matt Math 🥫 :
Further proof that e is hiding everywhere
2022-12-28 21:49:19
1
chosenthree🇨🇦 :
I guessed that. larger exponent is intuitively larger. I need to understand your explanation. been a while doing limits and e. looks neat though
2023-01-03 16:42:36
1
Brandon :
Was this an amc question?
2022-12-30 16:16:27
0
csblb 🇧🇪 :
Very good one 👍
2022-12-28 21:48:07
1
🍍👍 :
No cuz if you look in the video and my example, they both match up if the lower value is "n": n^n+1 and (n+1)^n - I hope this makes sense, if not, ask
2022-12-28 23:58:17
0
b_runner2022 :
I did it by pattern recognition and extrapolated the data. starting 3^4 vs 4^3 the smaller coefficient always ended up being bigger 🙂
2022-12-28 22:11:06
1
Marsellus Wallace :
Can you use e like that for any other variables?
2022-12-28 23:17:57
0
Cary Huang :
Ooooh I was thinking of taking the log of both sides, which eventually gets you to asking if log(2023) is at least 2023/2022 * log(2022) (it’s not)
2022-12-28 23:48:20
2
Tmc Tmc :
x^(1/x) has maxima at e.
2022-12-29 18:49:15
0
🍍👍 :
I felt like it was obvious because it's only one less but raised to the next power. 3^2=9 and 2^3=8 (I didn't finish the video before writing this)
2022-12-28 20:46:46
25
Andrés Romero | Matemáticas :
Wooow you really blew my mind with this one. That plot twist with e was amazing. Math really feels like a movie sometimes XD
2022-12-28 20:40:47
13
user1303241644744 :
You talked too fast to understand what you were trying to explain here. And when you randomly bring in e you lost me.
2022-12-28 22:43:28
0
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