According to MY CALCULATIONS 134=raised to 15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 84) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) as you know 9 - x² produces y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7)= IS 134=raised to 15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4
answer is 21 spoons of sugar
PLS LIKE THIS😭
2026-04-20 10:52:54
1
Choruatt :
The mistake is taking the sqrt and not writing absolute values.
Without it you have that a positive number x-3 is equal to a negative number x-pi.
2023-07-14 19:40:41
90
The Rusty :
I'm disappointed that less and less problems are equal to 69, 419 or 420. ☹️
2023-07-14 20:56:09
228
The true minecrafter :
When you added x^2 the plus and minus swapped for no reason
2023-07-14 19:30:26
107
AndyMath.com :
Mistake identified at 1:45.
2023-07-14 19:30:25
79
Rumi>< :
WHY IS MATH ON MY FYP😭😭
2025-04-17 00:16:07
37
meltingkeith :
Mistake is when you multiplied by 0 in the second line
2023-07-15 00:25:16
59
𝔯𝔶𝔞𝔫. ꏂ3 :
mistake is second step
2026-05-11 10:53:32
0
🦅🇪🇦david🇪🇦🦅 :
you can't multiply by 0
(π-3)
2023-07-14 20:10:40
9
Tristan :
if pi = 3 so you can't multiply by pi-3 ??? so anyway this is wrong
2023-07-14 19:42:16
12
Get real :
#proud I found it while you were talking but I hadn't rationalized the reason why it was the mistake before you said the reason
2023-07-14 20:15:35
6
Michel vanessa :
I was always bad at math ❤❤❤
2026-01-23 17:57:41
1
Paul Petrovai :
If you multiply by pi-3 and pi=3 the operation is not defined as you can't multiply by 0
2023-07-16 16:12:10
9
পরিবারের বড় ছেলে :
hello sur
2026-01-10 09:23:11
3
rx math :
great lesson on absolute value!
2023-07-14 20:35:40
10
twang :
I feel like most of these spot the mistake math videos involve something with squares and square roots
2023-07-16 21:43:24
6
frz :
kenapa isinya inggris semua
2026-02-06 09:10:56
0
Neal Golub :
Since x-pi is negative, radical (x-pi)**2 is not x-pi, it is -(x-pi)
2023-07-24 17:41:01
5
Prin-cess💗🇷🇴 :
i don't like maths🤣
2025-09-20 18:16:37
5
ciaooooooo111122 :
You can’t multiply or divide by zero so if you multiply by pi-3 this quantity mustn’t be zero. Hence pi mustn’t be three
2023-07-15 12:14:51
1
Far2deep :
I in fact did not find the mistake, in fact I was the mistake 🙃
2023-07-15 14:28:23
4
The_Truth :
|x -3|=|x -π|
2023-07-16 14:45:52
3
🔥 Mustapha 🔥 :
The square root supposed to have (plus or minus), which will disrupt the solution
2025-12-03 16:29:11
1
I’m In Your Walls :
Should be x - 3 = pi - x not x - 3 = x - pi
2023-07-14 20:45:59
4
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