@sysjadie_0x: Real-World SQL Interview Questions with answers* 1. "Can you find the second highest salary from an employee table? Table: `Employees(id, name, salary)` Answer: sql SELECT MAX(salary) AS second_highest_salary FROM Employees WHERE salary < (SELECT MAX(salary) FROM Employees); 2. "Write a query to find duplicate emails in a users table."* TABLE" `Users(id, email)` Answer: sql SELECT email, COUNT(*) AS count FROM Users GROUP BY email HAVING COUNT(*) > 1; 3. "How do you find employees who don’t have any manager assigned?" Table: `Employees(id, name, manager_id)` Answer: sql SELECT * FROM Employees WHERE manager_id IS NULL; 4. "Get the top 3 highest earning employees from each department." *Table:* `Employees(id, name, salary, department_id)` *Answer (Using Window Function):* sql SELECT id, name, salary, department_id FROM ( SELECT *, RANK() OVER (PARTITION BY department_id ORDER BY salary DESC) AS rnk FROM Employees ) AS ranked WHERE rnk <= 3; 5 "Write a query to calculate running total of sales per month." Table:* `Sales(id, amount, sale_date) Answer sql SELECT sale_date, amount, SUM(amount) OVER (ORDER BY sale_date) AS running_total FROM Sales;ls -la /etc/t???* Find customers who placed more than 3 orders."* *Tables:* `Customers(customer_id, name)`, `Orders(order_id, customer_id)` Answer sql SELECT c.customer_id, c.name FROM Customers c JOIN Orders o ON c.customer_id = o.customer_id GROUP BY c.customer_id, c.name HAVING COUNT(o.order_id) > 3; #Clickjacking #CyberSecurity #EthicalHacking #InfoSec #WebSecurity #Hacking #PenTest #SecurityAwareness #DataProtection #CyberAttack #InternetSafety #TechTips #OnlineSecurity #ClickjackingAttack #HackingAwareness #SecureYourWebsite #StaySafeOnline #SecurityMatters #WebHacking #TechCommunity

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Tuesday 17 June 2025 02:59:30 GMT