@health.technologi5: BLS Workshop If a patient collapses on the road: First is seen safety Check response No Response patient the breathing to give recovery position Check pulse No breathing and no response and no pulse start Start effective CPR Call for help 1122 Health Technologist#viralvideo #foryoupage #trendingsong #unfreezemyacount #healthtechnology
health technology kawal ya health technicain kawal zan sara zayaty da ma health technicain kara dy os bs surgical koma mata pkr wo chy health technicain mai okro os za health technology waka kho na da asy fazol degree da awo na pak ky scop shta awo na out off country ka shy paisy gatal gawary no surgical join ky hes charta ba mar na khory
2025-08-31 10:04:08
1
🫀حسن پرست 🦋 :
great 👍
2025-08-30 18:45:42
5
💟💕Abdul basit bangash❣️💟💕 :
گرانہ دہ کم زے دے
2025-09-24 12:48:43
1
_𝓱𝓪𝓷𝓪𝓷❤️ :
Mara 😂
2025-09-01 05:58:56
0
⚔️🌲🍁 ₩₳ⱠłĐ ₳₣ⱤłĐł🍁 🌲⚔️ :
ICRC Trening ❤❤
2025-09-02 07:37:01
0
🔥دیروجی🔥 :
da wal 🥰
2025-09-01 17:47:15
0
Naseer jani 🥰 890 :
😂😂😆Dr pepper
2025-09-02 09:18:49
0
💟💕Abdul basit bangash❣️💟💕 :
دہ کم زے دے او سہ سوے دے پہ دے
2025-09-02 13:24:47
0
bilalkhan123 :
nicee
2025-08-31 16:31:40
0
Anesthesiologist :
i☺️☺️☺️☺️
2025-09-01 15:56:41
0
Dr❤ Momin ❤Bahar❤ :
سومره عالی🥰🥰🥰
2025-09-11 15:01:56
0
Rafiq khan 10 :
ameer sab ho bal ta ishara oke waye os warsa Sa oko 🤔
2025-09-01 21:07:36
0
🕯️𝐌𝐚𝐬𝐡𝐚𝐥 𝐊𝐡𝐚𝐧 :
rogh sarai mar na kai 😜
2025-09-01 18:28:46
3
Medico 🩺 💊💉 :
bro😂
2025-08-31 03:19:58
3
Ilyas Marwat :
800-1+299x = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7)
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7)
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) como saben 9 - x² produce y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) = A