What math class would a problem like this appear in?
2025-12-23 20:36:40
5
monkeyboypotter :
You appear to be claiming that |-i|=i. Why?
2025-12-24 03:06:05
13
ofek :
but it’s ln(abs(i)) and since abs(i)=1 wouldn’t the ln be 0?
2025-12-24 13:38:30
4
laze :
isnt |i| = 1 => ln|i| = ln(1) = 0
2025-12-23 21:56:20
4
Salt no limit :
Isn’t it just arctan1 - arctan0 ?
2025-12-26 20:16:22
3
Axel :
Ive never thought of trying to solve this integral this way i always go to residue theorem this is amazing.
2025-12-23 21:24:01
5
Zilyph :
Given that you’re integrating over the complex plane now ln is defined for negative numbers so shouldn’t you not use the absolute value when integrating, this also gives the correct answer
2025-12-24 00:59:59
5
eenhoornregenboogprinses :
i love your videos! there so cool and i learn something new everytime
2026-01-01 23:47:54
2
angle :
Sick 🔥🔥🔥
2025-12-23 20:37:43
0
يحيى :
bro its just arctan(x) 🙏🙏
2026-02-02 15:27:16
1
malek :
i solved it at high school using euler identity and i got -arccos(x/sqrt(x²+1))+c
2025-12-23 23:49:35
5
benimaru :
why not just do trig sub?
2026-01-25 18:18:38
0
Filip :
Can you solve this?
2025-12-24 19:55:43
1
vagoberto :
beautiful! but at some point (near the end) you just forgot to take the absolute values ln|i| and the answer would be different.
2025-12-23 20:58:44
3
EL Saam 🇱🇧 Ben Knaan :
why not write x² + 1 = x² - [e^(iπ/2)]²
2025-12-24 06:04:14
1
doubt_and_believe :
Maybe I'll introduce this question in my teaching events.
2026-01-14 11:37:22
0
9tobio1 :
Why is there some disrespect to x???
2025-12-25 18:24:10
0
rdborg :
lovely
2025-12-25 12:51:16
0
好可怕哦! :
pi/4
2026-02-01 06:47:52
0
Hakeem :
where is it used in real life?
2026-01-27 12:51:19
0
Luke :
just put the arc in the tan bro ✌️
2026-03-19 11:12:02
0
Chemical kid :
I just used arctan?
2026-01-04 04:23:55
0
Nhlanhla Ndlelayenkosi Dlamini :
interesting
2025-12-23 20:40:12
0
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