@polymathematic: New year, new numbers. Using only the digits 2, 0, 2, and 6, can we build every digit from 0 through 9? All operations allowed. Bonus points for keeping the digits in order. Some fall instantly. Others fight back just enough to get interesting. Can you find 4–9?

polymathematic
polymathematic
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Friday 23 January 2026 00:07:10 GMT
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kharms61
kharms :
(2^0)/(2/6)=3
2026-01-23 01:15:11
23
pokoire
pokoire :
Thought we were doing a factorial of the whole thing for a second when the video first popped up..
2026-01-23 00:25:10
38
hoyhwme
Rhea :
why not just 2^(0*2*6)?
2026-01-23 00:12:27
7
naumtrandos
⃝꙰⃝꙰⃝꙰⃝꙰⃝꙰⃝꙰⃝꙰⃝꙰⃝꙰⃝ NaumBro :
2+0×2+|cos(6!°)|=3
2026-07-05 12:05:00
0
hassan.sharieff
hassan :
2 + (0 * 2 * 6)! =3, unless this breaks the rule
2026-01-23 01:39:43
2
tjktokdad
Tuck :
(20/2)-6=4 ((2+0)/-2)+6=5 (are negatives allowed?) (2×0×2)+6=6 ((2+0)/2)+6=7 (2×0)+2+6=8 2!+0+2+6=9 (also iffy)
2026-01-23 00:22:28
2
rieri_shrimp
Rieri_Shrimp :
I got ((2*0)!/2)*6 = 3 |2*0+2-6| = 4 and |((2+0)/2)-6| = 5 but those feel like cheating
2026-01-23 04:41:33
7
bnc.aszd
bnc.aszd :
2+((0*2*6)!)
2026-01-23 22:16:15
1
m4ck3nz
️ M4ck3nz ★ :
((2+0!)^2)-6 =3
2026-01-26 23:06:46
0
dividebyeven
stevenlibby145 :
1 = 2^(0*2*6)
2026-01-23 23:50:47
0
did_i_say_that1
DidISayThat :
I was thinking 2+(0*2*6)!=3.
2026-01-24 05:49:54
0
mwitherell1
Michael :
this reminds me of something my fourth grade teacher assigned, that I loved. roll a 10ish sided die 5 times, and use those numbers in the same manner to get solutions of 1 - 60. the one homework I spent hours doing and thoroughly enjoyed. can't remember what it was called though 😭
2026-01-23 12:47:24
1
jpjp00love
JayPee :
first
2026-01-23 00:12:12
1
statmandu
chris :
2 + (0*2*6)! = 3
2026-01-29 18:04:05
0
juusto89
Juustoo :
*math*
2026-01-24 22:36:45
0
shiversray
Shivers :
Cause u have done 2^0^2^6 for 1
2026-01-23 17:40:29
1
samuraino.28
That one thought :
you could have done 2 + (0×2×6)! to get 3 2 × 0 - 2! + 6 for 4 - (2×0×2)! + 6 for 5 2×0×(2!) + 6 for 6 (2×0×2)! + 6 for 7 (2×0) + 2! + 6 for 8 (2×0)! + 2 + 6 for 9
2026-01-28 12:41:57
0
kevinsuperoctave
Kevin St. Hill :
((2^0)^2)^6 = 1
2026-01-25 14:37:40
0
mochammad.fariya
দুষ্টু ভাবীর মিষ্টি ননদ :
🥰
2026-02-08 12:41:13
0
mmm.......mufasa
Mufasa :
2*0-2+6=4 20/2-6=4 (-2-0)/2+6=5 2*0*2+6=6 2-0/2+6=7 2*0+2+6=8 Nine i cant figure
2026-01-27 13:24:28
0
eyal7373
Eyal :
2 *0 *2 *6 = 0 (2^0) *2 *6 = 1 2+(0* 2 * 6) =2 -(2^0) - 2 +6 =3 (2*0) -2 +6 = 4 2^0 -2 + 6 = 5 (2*0*2) + 6 = 6 ((2^0)^2) + 6 = 7 (2*0) +2 +6 = 8 2^0 +2 +6 = 9
2026-01-23 03:14:53
0
eyal7373
Eyal :
2 *0 *2 *6 = 0 (2*0*2*6)! = 1 2+(0* 2 * 6) =2 2+ (0 *2 *6)! =3 (2*0) -2 +6 = 4 2^0 -2 + 6 = 5 (2*0*2) + 6 = 6 ((2^0)^2) + 6 = 7 (2*0) +2 +6 = 8 2^0 +2 +6 = 9
2026-01-23 03:11:07
3
peteh61
Pete H61 :
[(2 + 0) ÷ 2] ^ 6 = 1 2 + (0 × 2 × 6) = 2 2 ^ 0 + 2 mod 6 = 3 (2 + 0 + 2) mod 6 = 4 (2 + 0! + 2) mod 6 = 5 (2 × 0 × 2) +6 = 6 2 + 0! - 2 + 6 = 7 (2 × 0) + 2 + 6 = 8 (2 + 0!)! ÷ 2 + 6 = 9
2026-01-24 00:06:17
0
dinnerplz
Kate :
(2 + 0) / 2 % 6 = 1 2 ^ (0 * 2 * 6) = 1 20 >> (-2 + 6)= 1 (binary operators) (2 + 0) / log(-2 + 6) = 1 (log base 2 kida cheating) (20 - 2) / 6!!! = 1 (triple factorial)
2026-01-28 01:57:53
0
peterkingo2
Peter King :
4 = -2^0(2-6)
2026-01-23 00:24:47
1
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