@the.edgy.reel: SAVE ME MJ😂haha#spiderman #zendaya #fyp #bloopers #behindthescenes

The Edgy Reel
The Edgy Reel
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Friday 20 March 2026 11:02:31 GMT
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yourmom_yourdad22
yourmom_yourdad22 :
"am I fired?"
2026-03-20 12:56:56
16390
perpetual.cosmos
Vix 🦊 (Avon) :
idk why but him saying "I was trying so hard not to sneeze" makes me giggle so much
2026-03-20 12:36:15
3377
hannahbrindley4
Hannah Brindley :
They must’ve had so much fun making these movies 😭
2026-03-21 17:25:13
870
pilot_1855
Nardo proto :
"save me MJ" 🤣🤣🤣
2026-03-21 16:49:37
1949
tiktokdelenquent
Delinquent :
I miss the days where they include the bloopers in the movie
2026-03-21 14:57:48
733
user.38484828
Hoàng Việt Chi :
my parents are dead
2026-03-22 09:52:57
343
h_jxmes07
Hannah❤️ :
why is it giving that one baby
2026-03-20 19:55:03
1416
tevin_galvin
tevin :
2026-03-21 10:45:01
418
ginobertucci
ginobertucci :
Wish they would put bloopers back in at the end of the movie especially when you go to the theaters would make it more worth going to see
2026-03-21 19:49:15
600
kee2106
⋆. 𐙚˚࿔ Kee 𝜗𝜚˚⋆ :
“Am I fired”
2026-03-25 17:17:49
189
sofi.vibes47
1n_onlysoff :
PETER MAN
2026-03-20 21:48:22
746
oliver_13630
Ole :
“My parents are dead”
2026-03-22 14:49:44
228
kairamonkleyshort_
kairamonkleyshort_ :
“Save me MJ” 😂😂
2026-04-20 10:37:42
20
ahhhhhhhyes1234
D red fellowgue :
My parents are dead
2026-04-04 08:17:34
10
dominicprod
Dominicprod :
2026-03-22 13:31:38
106
lorulianbunnyhood
LorulianBunny :
my parents are DEAD 😃
2026-03-21 22:06:28
44
elijahj97
Elijah :
wings and tings 😂
2026-03-22 01:51:10
82
user649393474758
Frances ✪ 🕸️ ⎊ :
PETER MAN 😭
2026-03-21 21:56:27
34
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#explosion #nuke #acceleration #fyp #accelerationism fully grasp Graham's number, labeled as \(G\) or \(g_{64}\), we must break down a number so large that standard mathematics completely breaks down when trying to write it. It is not infinity; it is a exact, finite whole number, but its scale is entirely beyond physical reality.1. Understanding Knuth's Up-Arrow NotationTo understand how Graham's number is built, we must first understand the operator used to construct it. Knuth's up-arrow notation extends basic arithmetic operations beyond addition, multiplication, and exponentiation.Let us define the progression of these operations using the base number \(3\):Level 1: Multiplication (Repeated Addition)\(3\times 3=3+3+3=9\)Level 2: Exponentiation (Repeated Multiplication)\(3\uparrow 3=3^{3}=3\times 3\times 3=27\)Level 3: Tetration (Repeated Exponentiation)Two arrows (\(\uparrow\uparrow\)) mean you create a
#explosion #nuke #acceleration #fyp #accelerationism fully grasp Graham's number, labeled as \(G\) or \(g_{64}\), we must break down a number so large that standard mathematics completely breaks down when trying to write it. It is not infinity; it is a exact, finite whole number, but its scale is entirely beyond physical reality.1. Understanding Knuth's Up-Arrow NotationTo understand how Graham's number is built, we must first understand the operator used to construct it. Knuth's up-arrow notation extends basic arithmetic operations beyond addition, multiplication, and exponentiation.Let us define the progression of these operations using the base number \(3\):Level 1: Multiplication (Repeated Addition)\(3\times 3=3+3+3=9\)Level 2: Exponentiation (Repeated Multiplication)\(3\uparrow 3=3^{3}=3\times 3\times 3=27\)Level 3: Tetration (Repeated Exponentiation)Two arrows (\(\uparrow\uparrow\)) mean you create a "power tower" of \(3\)s, where the height of the tower is determined by the number after the arrows.\(3\uparrow \uparrow 3=3^{3^{3}}=3^{27}=7,625,597,484,987\)Level 4: Pentation (Repeated Tetration)Three arrows (\(\uparrow\uparrow\uparrow\)) mean you repeat the tetration operation. The number of towers you stack depends on the previous result.\(3\uparrow \uparrow \uparrow 3=3\uparrow \uparrow (3\uparrow \uparrow 3)=3\uparrow \uparrow 7,625,597,484,987\)This creates a power tower of \(3\)s that is 7.6 trillion layers tall. You cannot write this number down, even if every atom in the universe turned into ink.2. Building the 64 Layers of Graham's NumberGraham's number does not stop at three arrows. It uses a 64-layer recursive sequence where the number of arrows in one layer is determined by the total value of the previous layer.Let us define the sequence step-by-step:Layer 1 (\(g_{1}\))The sequence begins with four up-arrows:\(g_{1}=3\uparrow \uparrow \uparrow \uparrow 3\)To solve \(g_{1}\), you must calculate:\(g_{1}=3\uparrow \uparrow \uparrow (3\uparrow \uparrow \uparrow 3)\)We already established that \(3 \uparrow\uparrow\uparrow 3\) is a power tower 7.6 trillion layers tall. Therefore, \(g_{1}\) is a power tower of \(3\)s whose height is equal to that un-writable 7.6-trillion-layer number.Layer 2 (\(g_{2}\))\(g_{2}=3\uparrow \dots \dots \dots \uparrow 3\)The number of up-arrows between these two \(3\)s is exactly equal to the value of \(g_{1}\).Layer 3 (\(g_{3}\))\(g_{3}=3\uparrow \dots \dots \dots \uparrow 3\)The number of up-arrows between these two \(3\)s is equal to the value of \(g_{2}\).The Final Step (\(g_{64}\))This process continues sequentially for 64 iterations:\(\text{Graham}^{\prime }\text{s\ Number\ }(G)=g_{64}\)Layer 64: g_64 = 3 ↑↑↑... ...↑↑↑ 3 <--- This is Graham's Number \ / g_63 arrows . . Layer 3: g_3 = 3 ↑↑↑... ...↑↑↑ 3 \ / g_2 arrows Layer 2: g_2 = 3 ↑↑↑... ...↑↑↑ 3 \ / g_1 arrows Layer 1: g_1 = 3 ↑↑↑↑ 3 3. The Ramsey Theory Problem It SolvesRonald Graham did not create this number simply to make a large value. It was calculated as an upper bound to solve a specific problem in a branch of combinatorics called Ramsey theory, which looks for guaranteed order within chaos.The problem can be visualized through dimensions:The Setup: Imagine an \(n\)-dimensional hypercube (a cube extended into any number of dimensions).The Connections: Connect every single vertex (corner) of this hypercube to every other vertex using lines. This forms a complete graph.The Coloring: Color every single one of those connecting lines using only two colors: blue or red.The Question: What is the minimum number of dimensions (\(n\)) required to guarantee that, no matter how randomly you color the lines, there will always exist a single-colored flat plane connecting four vertices?Graham proved that a dimension size exists where this

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