@mathsteaching: Which one is correct? #maths #math #intothegroove #followthatchune

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Saturday 28 March 2026 10:13:49 GMT
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iamlucyonearth
lucyyy :
The second one, you cant just cancel terms out that are not equal. x is multiplied by y and 5 and you cant assume y=5
2026-03-28 10:16:41
386
will._62
Will :
both are correct
2026-03-28 13:16:37
114
mike.wang2012
MikeTheMikey :
when x is 0, y is anything, when y is 5, x is anything
2026-03-28 15:42:09
108
will.stimo
will :
neither. infinitely many solutions as a single equation with 2 variables cannot be solved
2026-03-28 23:49:49
19
jzzzzzzzzzz81
DP52 :
if x is 0 we cant divide it by 0 (x)?
2026-05-10 00:27:38
1
f.cisco099
Currito :
No one, if x=0 then y= R. If y=5 then x= R
2026-03-28 21:06:57
10
bluecrackle
Cameron :
The seccond cause x=0 works as a solution and the first eliminates the possibility of x=0 therefore is invalid
2026-03-28 17:19:37
5
mosamozes
Mosa :
Neither. Answer: x=0, y = anything AND/OR y=5, x = anything
2026-03-28 14:37:20
6
joseph.georges03
JG :
x can be any number I think
2026-03-29 05:52:44
3
skibiditoiletlover12332
huzzbruzz :
neither
2026-03-28 23:43:00
0
_eash
Eash :
well if y=5 x can be any number do left is right
2026-03-28 21:37:57
2
paulconnolly653
paulconnolly653 :
X can be anything because you put x(5-y)=0 where y=5 that means x(0)=0
2026-03-28 13:29:35
0
horizon_1.1
Horizon :
2nd because the 1st assumes that x is not 0
2026-03-28 20:31:13
2
rose271332
rose271332 :
X is any number not just 0
2026-05-18 18:12:12
1
katzzyomom
katzzw🖤 :
no idea can u explain pls
2026-03-28 12:24:22
2
shaolin.11
shay💤 :
both are correct, but the second one is the "more correct" approach because when you do cancel out X, you're eliminating 1 possibly solution
2026-03-31 21:48:06
2
nastjatydgat
Nastja Tydgat :
both are right
2026-03-28 16:18:03
2
user2869519313611
︎ :
both are correct just that in the first one you would have to substitute y with 5 to get x
2026-03-28 14:28:56
1
tomrose487
tomrose487 :
First is better. It let's us put back in y to get 5x=5x which shows that x is any value not just 0.
2026-03-28 13:30:18
0
l3sbian_axolotl
Luca ✨🌸🔮 :
The first one is correct, as x could be any real number, not just 0.
2026-03-28 18:26:08
1
a.username.please
Ashe☭ :
you can't divide by any term unless you can show 0 isn't a solution
2026-03-28 19:31:27
1
wizdabest1
Wiz :
The second method is correct but you ended it wrong. The solution is either x = 0 or y = 5 not necessarily both. If x = 0, y can be any number, if y = 5, x can be any number.
2026-03-29 19:39:38
1
serena_1666
serena_1666 :
both are correct but you still gotta put y=5 in the formula for x but i usually use the right
2026-03-28 19:50:52
1
emoforgary
Luka :
left is more correct. Y=5 but x can be anything
2026-03-30 17:42:36
0
byanyother_
ByAnyOther_ :
Infinitely many solutions 👍
2026-04-11 08:39:41
0
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