@sumsofanarchyofficial: Okay, let’s have a look at a proof. We can write any multiplication from 6x6 to 10x10 as: (10-A)(10-B) where A and B are just the differences between the numbers and 10. For example, 6x8 would be (10-4)(10-2). Now we can multiply those brackets (we multiply each term in the first bracket by each term in the second bracket): (10-A)(10-B) =100 - 10B - 10A + AB Now, the first three terms are all multiples of 10, so we can pull that 10 out and see what’s left: =10(10-B-A) + AB But 10-B-A is the same as 10-(B+A) so we’ve got: 10[10-(B+A)] + AB The first bit matches up with counting in tens for the fingers on and below the joining line. We’re essentially subtracting the fingers above the line, which are the differences between our numbers and 10. The AB matches up to the loose fingers we multiply above the line, the differences between our numbers and 10. Algecadabra 🥰 ➕ ➖ ✖️ ➗ #multiplication #timestables #mathstricks #mathhacks #maths Referenced video: Dr Sinske’s Learning Center

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Saturday 04 April 2026 07:38:08 GMT