Quantum tunneling is nearly impossible for macroscopic objects because the probability of the event decreases exponentially with both the mass of the object and the thickness of the barrier. While a single subatomic particle like an electron can slip through a potential energy barrier, a large object like a person consists of trillions upon trillions of atoms that would all have to tunnel simultaneously. The mathematical likelihood of every single constituent particle appearing on the other side of a wall in perfect unison is so low that it is estimated at approximately one in \(10^{10^{23}}\), a number far exceeding the total count of atoms in the observable universe. Furthermore, macroscopic systems suffer from a phenomenon called decoherence, where constant interactions with the environment "measure" the object's position and collapse its delicate quantum wave function. Because these objects are so heavily entangled with their surroundings, they cannot maintain the coherent superposition required for the wave-like properties of tunneling to manifest on a large scale. Even if you were to wait for an astronomical amount of time—trillions of times longer than the current age of the universe—the chances remain virtually zero for any observable object. Additionally, the energy barriers presented by solid matter are far too wide and intense for the "probability waves" of heavy objects to penetrate with any measurable amplitude. Consequently, while tunneling is a vital reality for the sun's nuclear fusion and modern electronics, it remains a practical impossibility for the physical world we inhabit. For all human purposes, these laws of physics ensure that solid objects remain solid and do not spontaneously drift through walls.
2026-05-07 18:01:48
28
️ :
Quantum tunneling is nearly impossible for macroscopic objects because the probability of the event decreases exponentially with both the mass of the object and the thickness of the barrier. While a single subatomic particle like an electron can slip through a potential energy barrier, a large object like a person consists of trillions upon trillions of atoms that would all have to tunnel simultaneously. The mathematical likelihood of every single constituent particle appearing on the other side of a wall in perfect unison is so low that it is estimated at approximately one in \(10^{10^{23}}\), a number far exceeding the total count of atoms in the observable universe. Furthermore, macroscopic systems suffer from a phenomenon called decoherence, where constant interactions with the environment "measure" the object's position and collapse its delicate quantum wave function. Because these objects are so heavily entangled with their surroundings, they cannot maintain the coherent superposition required for the wave-like properties of tunneling to manifest on a large scale. Even if you were to wait for an astronomical amount of time—trillions of times longer than the current age of the universe—the chances remain virtually zero for any observable object. Additionally, the energy barriers presented by solid matter are far too wide and intense for the "probability waves" of heavy objects to penetrate with any measurable amplitude. Consequently, while tunneling is a vital reality for the sun's nuclear fusion and modern electronics, it remains a practical impossibility for the physical world we inhabit. For all human purposes, these laws of physics ensure that solid objects remain solid and do not spontaneously drift through walls.So that is edited
2026-06-06 01:54:00
2
lehlogonoloraphad6 :
are we deadass its a fucking toilet paper
2026-05-23 06:36:00
154
🃏𝓦𝓐𝓨𝓛𝓞𝓝̃🀄️ :
15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 84) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) as you know 9 - x² produces y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7)= IS 134=raised to 15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4
answer is 2
2026-05-29 01:08:14
25
dany_FCM :
que pasaría si me caigo y los átomos se juntan qué me pasaria?
2026-06-02 00:11:41
7
♦A♦ :
2026-05-04 09:23:08
282
Roy :
Rate my summer outfit
2026-05-11 14:31:02
23
PDZZIN77 :
eu fiz algumas pesquisas,os átomos se alinharem é teoricamente possível,mas para o ser humano que contém octilhões deles essa chance é quase impossível,mas tem uma chance de 0,00000...(cerca de mais 100 decilhões de zeros) disso realmente acontecer.Na matemática 10⁵⁰ é impossível ja esse número é 10¹⁰ e esse 10¹⁰ elevado a 35.
CURIOSIDADE:esse número é tão massivo que caso ele fosse mostrado por inteiro em um computador a energia utilizada seria tão massiva que acabaria abrindo um buraco negro
2026-05-13 01:47:42
15
>u< :
it broke.
2026-05-17 05:47:25
26
ᵒ̴̶̷̤ꇴᵒ̴̶̷̤ toestyˏˋ°•*⁀➷ :
why are people taking ts seriously
2026-05-19 02:28:23
10
nj_vr24 :
Esta en los backrooms
2026-05-16 16:24:44
5
bintang :
itu bolong
2026-05-01 05:52:02
120
🐝🐝 bachirito🐝abejito🐝🐝 :
bro nosé si solo es humor pero si no lo es el papel solo c rompió
2026-05-01 19:48:52
910
' :
primeiro passo: 9 - x² da y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) como saben 9 - x² produce y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) =9
2026-05-22 19:55:06
6
itz.ian10 :
tell me how many now
2026-04-28 06:43:21
239
T.anis💫🍀 :
1+1=11 - x² da y = x + 79 - x² = x + 7 x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) como saben 9 - x² produce y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx
V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32)=16
2026-05-14 14:36:59
7
:
134=raised to 15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 -7 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 84) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) as you know 9 - x² produces y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7)= IS 134=raised to 15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x ² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4
my answer is idk Please like this took me FOREVER