Kesper
Region: ID
Saturday 02 May 2026 10:16:51 GMT
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pebyiipp🫧 :
nyambung jir😭
2026-05-10 08:49:54
2510
Kyyga_57 :
mas amba karaoke bersama mbak Sri loh ya😹
2026-05-05 04:22:28
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Chenzz DiCaprio :
tebak ending 😹
2026-05-05 09:23:24
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X Kings :
tebak kegiatan😹
2026-05-05 10:49:56
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GueAthaya🚀 :
mas rusdi megang mic aja kek gitu 😹
2026-05-07 03:49:39
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★ :
yg ngesave pada ngapain jir😹
2026-05-06 09:48:41
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😹 :
mas amba ngapain Lo ya😹
2026-05-07 08:11:53
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🤭 :
tumben hd
2026-05-10 23:17:20
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Syaaja❄️ :
own nya ganteng🥰🥰
2026-05-15 19:40:14
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firman :
"di grup ktanya besok"
2026-05-14 11:19:42
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Ken0x 멋있는 :
yg belakang
2026-05-09 07:03:07
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aiinorrr :
dia siapa sih😭
2026-05-05 15:58:31
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riyantov :
tebak ambu mobil😹
2026-05-05 13:17:59
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Alfyxz :
asik benget lho rek🤓
2026-05-08 10:42:20
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![Stop wasting time with long math steps on your exams! 🤫 Use this 5-second AM-GM formula cheat code to maximize products instantly. Save this video for your next test! 🧠✨ how AM-GM inequality drived How the AM-GM formula works for 3 variables: We use a famous identity for any three positive real numbers x, y, and z: x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx) We can rewrite the second part of that equation like this: x^2 + y^2 + z^2 - xy - yz - zx = 0.5 * [(x-y)^2 + (y-z)^2 + (z-x)^2] Since squares are never negative, this entire part is greater than or equal to 0: x^3 + y^3 + z^3 - 3xyz >= 0 x^3 + y^3 + z^3 >= 3xyz Now, substitute x with a^(1/3), y with b^(1/3), and z with c^(1/3): a + b + c >= 3 * (abc)^(1/3) Divide both sides by 3 to get the final formula: (a + b + c) / 3 >= (abc)^(1/3) This proves that the Arithmetic Mean is always greater than or equal to the Geometric Mean for 3 variables! #MathHacks #ExamShortcuts #MathTricks #AlgebraHack #SATPrep](/video/cover/7676521844878494997.webp)
