@manuellacosta00: It took me 7 years to notice these Eastereggs😱🤯#toystory #cars #disney #mystery #theory

Manuella Costa
Manuella Costa
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Region: US
Thursday 14 May 2026 15:00:00 GMT
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adong.malunes
Adong Malunes :
BNL meaning?
2026-05-18 01:43:33
34
kadiryilmaz9
📿alkapon-kerim🕶 :
BNL is proud of you now
2026-05-14 22:00:57
14
splashnaz
splashnaz :
Films made by the same company, using their own made up brand, perhaps?
2026-05-15 07:40:08
751
aisc405
Mr.no :
You now evry Disney Movie is in the Same ungewisse
2026-05-14 16:16:39
181
user1055589
K2991 :
What is your point?
2026-05-15 20:35:32
66
mbk01330
mbk01330 :
2026-05-14 18:40:46
192
simonlge47
Simon47 :
Normal quoi 😂 tout ces dessins animés son de pixar
2026-05-15 07:36:30
108
nolze76
Nolzey :
Just drink your coffee
2026-05-21 10:57:36
65
malgosiaaa_67
:) :
big brain
2026-05-14 15:02:26
141
juanm4011
Juan Morales🔥🖤☘️💯🔥🙏 :
Todas las películas son de la misma compañía y por eso usan sus mismos logos 😁😁
2026-05-26 01:03:44
13
xxthe.one.and.onlyxx
𝒯𝒽𝑒 𝒪𝓃𝑒 𝒜𝓃𝒹 𝒪𝓃𝓁𝓎 :
habt ihr immer noch nicht begriffen das in allen wirklich allen Disney Filmen Charaktere von anderen Filmen vorkommen.
2026-05-15 17:24:45
19
agnieszkajarosz84
Agnieszka Jarosz846 :
w każdym filmie w każdej bajce są przekazy!
2026-05-14 23:31:27
95
hagi616349191703
abrham123 :
i afraid the background sound of your videos
2026-05-31 19:22:59
9
nil08931
nil :
برای باتری نوشته بود bl بی ال فنا میفهمن
2026-06-12 11:31:06
10
artouage11
artouage :
2026-05-15 14:53:40
34
bibigoulotte
bibigoulotte :
Il s'agit de BnL (Buy n Large), l'entreprise fictive géante de l'univers Pixar. C'est un Easter egg récurrent : BnL est la méga-corporation omniprésente dans WALL-E (elle a pris le contrôle de l'économie mondiale et exploite le vaisseau Axiom). Pixar glisse son logo dans plusieurs autres films comme clin d'œil.
2026-05-29 03:03:31
9
la_menoltulipanes
la_menol tulipanes :
A=9 - x² da y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = Π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) como saben 9 - x² produce y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 1x⁴9)=1
2026-05-14 20:24:20
6
francescotodaro79
francescotodaro79 :
E quindi?
2026-05-16 04:45:29
9
janoelmontano
Ban cor :
Es copia del chico rubio no? Por que ese video lo vi hace tiempo
2026-07-06 12:24:28
9
srm71293
🎭Sr.M🎭 :
2026-05-16 19:25:22
17
behiindyou
behiindyou :
Wow, du hast nichts raus gefunden, gratulation 😂
2026-05-17 11:36:06
12
snaketruckandsing
Snake :
qui ne sait pas encore le nombre de ref qu'il y a dans tout les Pixar ... je suis sur il y en a même encore que personne n'a vu
2026-05-16 11:42:55
7
_espectro_libre
@Manco77 :
a lo mejor es una marca de pila y por eso es reconocida, no captan o que?
2026-05-14 22:54:22
9
vampirepenguin
Paul Reilly :
Pixar has numerous hidden messages in their films. A113 for example.
2026-05-15 00:41:59
104
triple.d062
triple d :
And wot u look so fit
2026-05-14 21:53:53
7
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