NotMathClub
Region: US
Friday 29 May 2026 15:42:01 GMT
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viki :
I won’t use it, no worries
2026-05-29 15:56:34
78
فيصل 🇦🇪🇱🇧🇵🇸 :
why not just add the arguments once both are in exponential form?
2026-05-29 15:54:44
8
Milo :
I noticed that if you multiply what's in the denominator by i you get the numerator (ignoring powers) and since i⁸=1 we can times the top and bottom by 1 or i⁸ to get (1+i√3)¹³/(1+i√3)⁸ = (1+i√3)⁵ which you can convert to polar form and simplify to 16-16i√3
2026-05-29 16:59:25
5
Heyweb1500 :
What calculus textbook in the back?
2026-05-31 22:30:56
0
Dr. DaViNci mathematician :
I started by taking -i as a common factor from the denominator which made me simplify the fraction into numerator power 5
2026-05-29 18:26:24
3
davyd :
What is that? A-level?
2026-05-31 00:26:16
0
Gabi :
why don't we put it into polar form then use de moivres theorem to simplify the exponents?
2026-05-29 17:06:50
1
akriloth :
holy crap, that is beautiful
2026-06-15 16:20:29
1
markp :
in going with DeMoirve's theorem ...which goes to the cis notation rather than the e^i theta ...but students learn DeMoirves in precalc but you need Taylor series to get to e^i theta
2026-05-29 19:44:45
5
Ibhaca🇿🇦🇸🇿LakwaGamedze :
de moivres theorem from the start would have surely helped 👍 😏without the fancy 2^13 😉
2026-06-15 22:25:26
1
purplec0de :
I would actually rather eat twenty plastic forks than multiply out anything raised to the fifth power, much less the 8th or 13th
2026-06-01 07:30:29
1
@krakrak🏳️🌈🇵🇱🇪🇺 :
I would calculate the angles of both numbers. Then 13*angle1 - 8*angle2 = angle of the answer. Then divide length1/length2 and we get the length of the answer
2026-06-01 13:01:32
1
purpleblossom :
(1+i√3)^13/(√3-i)^8 = (1+i√3)^13(√3+i)^8/2^8 = (1+i√3)^5 = (1-30+45)+(5-30+9)i√3 = 2^4(1-i√3)
2026-05-29 20:06:27
1
Richard :
That was slick 😎
2026-05-29 21:12:00
1
Juiceboy3090 :
dog where have you been I miss you!
2026-05-31 03:21:53
0
Shebby Maconcept🇹🇿🇬🇧🇹🇷 :
change into polar form
2026-05-30 07:26:17
0
imogen99.50 :
❤️
2026-05-30 12:28:53
0
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