@neves.scholar: Você já se perguntou quem inventou o π? Há mais de 4 mil anos, civilizações antigas já tentavam calcular a relação entre a circunferência de um círculo e seu diâmetro. Mas foi apenas no século XVIII que o símbolo π foi popularizado pelo matemático galês William Jones. O mais impressionante? O π é um número infinito. Seus dígitos nunca terminam e nunca seguem um padrão. Até hoje, cientistas utilizam o π em áreas como engenharia, física, astronomia e tecnologia. Um simples círculo ajudou a revelar um dos números mais fascinantes da história da matemática. #NevesScholar #foryou #viral #edit#matematica

Neves Scholar
Neves Scholar
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Saturday 30 May 2026 01:55:33 GMT
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lenovo3460
Sandro🇬🇪 :
no is it 23
2026-11-06 17:27:47
0
user3419637802796
user3419637802796 :
∞+∞=😅
2026-10-02 12:44:50
0
bonbon72381
🦉htut phone khant Kyaw🦉 :
2π[12z]+5π=0.9 easy bro 😂
2026-08-27 09:46:25
2
krishraiiiiiiiiii
tender :
π
2026-10-17 00:09:27
1
wybie295
wybie :
2026-10-31 06:43:05
2
phonephone2062
ခေတ်ဆည်းဆာ :
[Laugh approved][Laugh approved]1+1=2 2+2=4[Pray]
2026-10-07 09:17:31
1
jonaton.nskks
Jonaton Nskks :
✓π÷
2026-10-21 18:19:14
1
prisicarrillo
FARIDDGMR :
0•=+*^>€¥+#<||%+=[]=?
2026-10-17 02:05:33
1
chamilk999888
น้องชามิลล์ :
+2+43+26+5+4+3++32+2+9+0+9+8+7+8+6+5+4+3+2+1+0+9+8+7+6+5+4+3+2+2+4+0+9+8+7+6+5++2+1
2026-09-19 16:06:40
4
elliot.c179
𝙰 𝚁 𝙴 𝙽 :
π=94437357337876324784368.574367540054333236890008
2026-10-17 15:04:41
1
user5567655570141
ครอบครัวตัวกลม :
4+5=9
2026-10-20 07:02:50
1
b.sn1375
bá sàn :
29+_81_@+84-"+@8-!@828&-*(91+&!*9&72+:917!-9@+5!"917&+*(8274;₫)28&+")18&+#937&+8)&+18-(×[29&(#9+&818-(₫928&(#9-+*97"(93+₫848+₫92-+(#4+_
2026-10-15 05:26:12
1
maryeiniscuelloda
danaxeljordan :
π
2026-10-25 01:31:12
1
user77387524925427
มะ ดิว🎀 :
2+2=(5)฿#@(2<×;;@
2026-10-13 06:45:46
1
chai.heah.tan
Chai Heah Tan :
2026-10-27 04:00:23
1
clark_serra
mr_kurt708 :
72546$+_"(863(63+6293864887_+_(-_974+6_(_7367475$(76485+_(&64;:84496*-_+484+5_864+8&5+_86+_+++++++876387464848639473(837373737373737473+$-(6#8#63998@9837_(_('+π
2026-10-01 00:02:21
1
yasi7177
yasi :
2026-10-17 14:55:28
1
nyx4442
Nyx :
2026-10-20 16:05:04
1
fofofofo7648
ช้อน :
∞÷Π×5274∞×√π8∞
2026-10-18 08:55:13
1
anitajulianitafam
ANITA @ :
πππππππππππ∆∆ππ
2026-10-10 01:22:11
1
a5bbeka2
A5B :
100×100 10000
2026-09-25 08:33:48
1
_liliy_47
Meghan Adubal :
𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚇𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡 𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸𝚡𝟹-𝟽 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗𝚌𝚎𝚜 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝟿 - 𝚡² 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗𝚌𝚎𝚜 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡 𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸𝚡𝟹-𝟽 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-w)= 𝚡² 𝚍𝚊 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 6 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - 𝚡² 𝚍𝚊 𝚢 = 𝚡 +=∫
2026-10-02 08:25:41
1
yourpookies80
user71436238933 :
ms cin ♡: @ㄷㄴㅅㄱㄷㅏㅏㅁ☆:1+1=? กู:20+20×2=x² da y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) como saben 9 - x² produce y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V =π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 5 (14x 32) =2
2026-09-23 19:18:27
0
mutiara.amanda34
Mutiara Amanda :
√¥π
2026-11-02 08:15:45
0
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