@san.kana.07:

san.kana.07
san.kana.07
Open In TikTok:
Region: SN
Friday 05 June 2026 22:24:19 GMT
413
54
7
6

Music

Download

Comments

karim.falln
Thiatou Mamy 🥰🥰❤️⚽️ :
🥰🥰🥰
2026-06-06 21:50:07
0
layegana27
Laye gana 🚭@ djiwé 👿 gameur :
🥰
2026-06-06 15:52:10
0
ousseynou.kane033
weuz :
😁😁😁
2026-06-06 15:30:17
0
princepeulh123
DOU🇸🇳 :
❤️❤️❤️
2026-06-06 01:14:05
0
bakhe190
Bakhe 222 :
😳😳😳
2026-06-05 23:56:13
0
user1807233453991
user1807233453991 :
🥰🥰🥰
2026-06-05 23:18:30
0
boubs730
user9658685538183 pape bouba :
🥰🥰🥰
2026-06-16 14:52:43
0
To see more videos from user @san.kana.07, please go to the Tikwm homepage.

Other Videos

🧱📐 QUANTITY OF CEMENT AND SAND REQUIRED FOR PLASTER Prepared by: Kenechukwu Princewell Ken's Home Engineering & Construction Design. Engineer. Build. Accurate material estimation is essential for achieving a strong, durable, and cost-effective plaster finish while minimizing wastage and improving project budgeting. This example demonstrates the calculation of cement and sand required for plastering a wall area of 100 m² using a 12 mm plaster thickness and a 1:4 cement-sand mix ratio. 📌 GIVEN DATA ✅ Plaster Area = 100 m² ✅ Plaster Thickness = 12 mm ✅ Mix Ratio = 1:4 (Cement : Sand) ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 1: CALCULATE PLASTER AREA Assuming a wall measuring: Length = 10 m Height = 10 m Area = Length × Height Area = 10 × 10 Area = 100 m² ✅ Plaster Area = 100 m² ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 2: CONVERT PLASTER THICKNESS TO METRES Thickness = 12 mm 12 mm = 12 ÷ 1000 12 mm = 0.012 m ✅ Plaster Thickness = 0.012 m ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 3: CALCULATE WET VOLUME OF PLASTER Wet Volume = Area × Thickness Wet Volume = 100 × 0.012 Wet Volume = 1.20 m³ ✅ Wet Volume = 1.20 m³ ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 4: CONVERT WET VOLUME TO DRY VOLUME To account for voids, bulking, shrinkage, and site wastage, a dry volume factor of 1.62 is used for plaster work. Dry Volume = Wet Volume × 1.62 Dry Volume = 1.20 × 1.62 Dry Volume = 1.944 m³ ✅ Dry Volume = 1.944 m³ ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 5: DETERMINE TOTAL MIX PARTS Mix Ratio = 1 : 4 Cement = 1 Part Sand = 4 Parts Total Parts = 1 + 4 = 5 ✅ Total Mix Parts = 5 ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 6: CALCULATE CEMENT QUANTITY Cement Quantity = (1/5) × 1.944 Cement Quantity = 0.3888 m³ Volume of one 50 kg bag of cement = 0.0347 m³ Number of Bags = 0.3888 ÷ 0.0347 Number of Bags = 11.20 Bags Rounded for practical site application: ✅ Cement Required = 12 Bags of Cement (50 kg each) ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 7: CALCULATE SAND QUANTITY Sand Quantity = (4/5) × 1.944 Sand Quantity = 1.5552 m³ Convert to Cubic Feet: 1 m³ = 35.3147 ft³ Sand Quantity = 1.5552 × 35.3147 Sand Quantity = 54.91 ft³ ✅ Sand Required = 1.5552 m³ ✅ Equivalent to 54.91 ft³ ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 8: CONVERT SAND VOLUME TO TONNES Average bulk density of construction sand: 1 m³ of Sand ≈ 1.6 Tonnes Sand Weight = 1.5552 × 1.6 Sand Weight = 2.48832 Tonnes Rounded: ✅ Sand Required ≈ 2.49 Tonnes ━━━━━━━━━━━━━━━━━━━━━━ 📊 FINAL MATERIAL REQUIREMENT SUMMARY ✅ Plaster Area = 100 m² ✅ Plaster Thickness = 12 mm ✅ Wet Volume = 1.20 m³ ✅ Dry Volume = 1.944 m³ ✅ Mix Ratio = 1 : 4 ✅ Cement Quantity = 0.3888 m³ ✅ Cement Required = 12 Bags ✅ Sand Quantity = 1.5552 m³ ✅ Sand Quantity = 54.91 ft³ ✅ Sand Quantity = 2.49 Tonnes ━━━━━━━━━━━━━━━━━━━━━━ 🎯 IMPORTANCE OF ACCURATE PLASTER MATERIAL ESTIMATION ✔ Reduces material wastage ✔ Improves project budgeting ✔ Prevents material shortages ✔ Enhances procurement planning ✔ Ensures consistent plaster quality ✔ Improves site productivity and cost control This calculation method is essential for Civil Engineers, Builders, Quantity Surveyors, Contractors, Site Engineers, and Construction Students. Prepared by: Kenechukwu Princewell Ken's Home Engineering & Construction Design. Engineer. Build. Follow for more Civil Engineering and Construction Tips. #CivilEngineering #Construction #PlasterWork #MaterialEstimation #QuantitySurveying
🧱📐 QUANTITY OF CEMENT AND SAND REQUIRED FOR PLASTER Prepared by: Kenechukwu Princewell Ken's Home Engineering & Construction Design. Engineer. Build. Accurate material estimation is essential for achieving a strong, durable, and cost-effective plaster finish while minimizing wastage and improving project budgeting. This example demonstrates the calculation of cement and sand required for plastering a wall area of 100 m² using a 12 mm plaster thickness and a 1:4 cement-sand mix ratio. 📌 GIVEN DATA ✅ Plaster Area = 100 m² ✅ Plaster Thickness = 12 mm ✅ Mix Ratio = 1:4 (Cement : Sand) ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 1: CALCULATE PLASTER AREA Assuming a wall measuring: Length = 10 m Height = 10 m Area = Length × Height Area = 10 × 10 Area = 100 m² ✅ Plaster Area = 100 m² ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 2: CONVERT PLASTER THICKNESS TO METRES Thickness = 12 mm 12 mm = 12 ÷ 1000 12 mm = 0.012 m ✅ Plaster Thickness = 0.012 m ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 3: CALCULATE WET VOLUME OF PLASTER Wet Volume = Area × Thickness Wet Volume = 100 × 0.012 Wet Volume = 1.20 m³ ✅ Wet Volume = 1.20 m³ ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 4: CONVERT WET VOLUME TO DRY VOLUME To account for voids, bulking, shrinkage, and site wastage, a dry volume factor of 1.62 is used for plaster work. Dry Volume = Wet Volume × 1.62 Dry Volume = 1.20 × 1.62 Dry Volume = 1.944 m³ ✅ Dry Volume = 1.944 m³ ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 5: DETERMINE TOTAL MIX PARTS Mix Ratio = 1 : 4 Cement = 1 Part Sand = 4 Parts Total Parts = 1 + 4 = 5 ✅ Total Mix Parts = 5 ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 6: CALCULATE CEMENT QUANTITY Cement Quantity = (1/5) × 1.944 Cement Quantity = 0.3888 m³ Volume of one 50 kg bag of cement = 0.0347 m³ Number of Bags = 0.3888 ÷ 0.0347 Number of Bags = 11.20 Bags Rounded for practical site application: ✅ Cement Required = 12 Bags of Cement (50 kg each) ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 7: CALCULATE SAND QUANTITY Sand Quantity = (4/5) × 1.944 Sand Quantity = 1.5552 m³ Convert to Cubic Feet: 1 m³ = 35.3147 ft³ Sand Quantity = 1.5552 × 35.3147 Sand Quantity = 54.91 ft³ ✅ Sand Required = 1.5552 m³ ✅ Equivalent to 54.91 ft³ ━━━━━━━━━━━━━━━━━━━━━━ 📌 STEP 8: CONVERT SAND VOLUME TO TONNES Average bulk density of construction sand: 1 m³ of Sand ≈ 1.6 Tonnes Sand Weight = 1.5552 × 1.6 Sand Weight = 2.48832 Tonnes Rounded: ✅ Sand Required ≈ 2.49 Tonnes ━━━━━━━━━━━━━━━━━━━━━━ 📊 FINAL MATERIAL REQUIREMENT SUMMARY ✅ Plaster Area = 100 m² ✅ Plaster Thickness = 12 mm ✅ Wet Volume = 1.20 m³ ✅ Dry Volume = 1.944 m³ ✅ Mix Ratio = 1 : 4 ✅ Cement Quantity = 0.3888 m³ ✅ Cement Required = 12 Bags ✅ Sand Quantity = 1.5552 m³ ✅ Sand Quantity = 54.91 ft³ ✅ Sand Quantity = 2.49 Tonnes ━━━━━━━━━━━━━━━━━━━━━━ 🎯 IMPORTANCE OF ACCURATE PLASTER MATERIAL ESTIMATION ✔ Reduces material wastage ✔ Improves project budgeting ✔ Prevents material shortages ✔ Enhances procurement planning ✔ Ensures consistent plaster quality ✔ Improves site productivity and cost control This calculation method is essential for Civil Engineers, Builders, Quantity Surveyors, Contractors, Site Engineers, and Construction Students. Prepared by: Kenechukwu Princewell Ken's Home Engineering & Construction Design. Engineer. Build. Follow for more Civil Engineering and Construction Tips. #CivilEngineering #Construction #PlasterWork #MaterialEstimation #QuantitySurveying

About