This favors E2 because of steric hinderance. KOtBu is considered to be a strong bulky base but a poor nucleophile. SN2 is favored for as little hinderance as possible. Hence, E2 is great here not SN2. This is a strong base and favors Hoffmann product because if you went Zaitsev way, you would have steric class due to the bulky group.
2026-06-11 05:38:22
6
pat :
C
2026-06-25 09:43:45
1
zoie :
ure so smart
2026-06-11 10:37:39
1
uksl :
2026-06-11 16:39:00
3
mamakeda :
😂😂😂
2026-08-27 15:05:01
0
mamakeda :
😳😳😳
2026-08-27 15:05:01
0
Luis barba :
😳😳😳
2026-08-27 20:35:16
0
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