OneTapTutoring
Region: CA
Tuesday 16 June 2026 02:40:13 GMT
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█████ :
any quotient can be expressed in the form of a product as division and multiplication are inverses of each other. or you can use the power rule I guess, hmph.
2026-07-23 11:10:33
0
❍ :
wait till you realise quotient rule is the product rule
2026-06-16 11:59:16
166
Astolfo_Kys :
Just use the product rule on the quotient?
2026-06-16 21:40:38
3
Teep :
when u realise there’s nothing hard at all on differentiation
2026-06-16 21:22:43
69
astral :
You can always make the denominator (x)^-1 and product rule 😍😍😍
2026-06-16 04:27:03
22
Leon :
I don’t even bother remembering it, I just use product and chain rules
2026-06-16 22:16:42
3
A^2+ R+Y^n :
Is it just me or whenever I have like y=something that requires quotient, Ill multiply both sides by the denominator and then use implicit 😭
2026-06-16 17:50:12
5
wsupabg :
remember ur gf comes first (gf’) then ur friends (-fg’), if not then ur going to have go over with her mom (/g^2), (gf’-fg’)/(g^2) lol thats how i remembered it 😅
2026-07-14 20:01:06
0
lean🍀 :
R u deadass bro
2026-07-11 06:19:01
1
Benten_thousand _and_one :
Lmao u wrote is wrong aswell it should be 1/x+1* x-3
2026-06-17 05:29:22
0
Hgyb :
"over v^2" yeah fuh no
2026-06-22 15:51:29
2
𝚍𝚊𝚒𝚛𝚊𝚑𝚝 :
if you see the chain and product in it (best to express as negative exp) it goes much faster (less cognitive load)
2026-06-16 13:49:43
2
RozhRasti_ :
dawg especially if it has ln square roots and other stuff with it
2026-06-16 11:25:05
1
gasbug1 :
shortcut: take the determinate of the coefficients of the terms then divide by denomonator squared. in this case, numerator = det(1 1; 1 -3) = -4
2026-07-04 18:24:25
0
Tristan Thomas🤑 :
Just do (x+1)(x-3)^-1
2026-06-29 16:00:09
0
:
chain and logarithmic>>
2026-06-16 13:33:38
1
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