Math with Jo MPA
Region: US
Monday 22 June 2026 22:50:31 GMT
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mash :
This was actually light
2026-06-23 03:44:22
41
dayriderBusking :
(n-2)(n-3) consecutive numbers, so always even x odd, so always has 2 as a factor. So only possible prime value is 2 n²-5n+6=2 n²-5n+4=0 quadratic: two solutions. this can factories, so two integer solutions
2026-06-25 13:36:50
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kan :
watching this without sound right now, and i have no idea where all these numbers are coming from😭
2026-06-22 23:34:11
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CSense :
I can’t believe (for the first time) I got the answer before it was buzzed 😭
2026-06-25 23:38:58
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DVRIIVE :
the one easy question 💔 ts prolly question 1 or smth
2026-07-04 09:57:55
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College Factor :
Great explanation that gives us an intuition for the problem.
2026-06-25 12:28:21
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Maslah Marshal :
you solved it wrong man! the two positive integers are 2 and 3 so they are (2 +ve integers)
2026-07-04 18:07:35
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Felix :
(n-2)(n-3) or (3-n)(2-n) one of the 2 factors needs to be 1, without the other being equal to 0. works for n=1 and n=4
2026-06-22 23:36:42
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𝕬𝖕𝖊𝖓𝖉𝖗𝖆❤️🔥 :
🔥🔥🔥
2026-07-01 13:46:35
0
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