In mathematics, (3 - 3) means "zero (0)". Therefore, dividing by (3 - 3) becomes "dividing by zero (0)". In mathematical rules, dividing any number by zero (0) is strictly not allowed (it is called "Undefined").
2026-08-25 13:11:25
0
Li'AK :
1+1=3 is false because
you ans is 2=3
1+1=3 so 1+1=2 why
1+1 is ~ 2
2026-08-25 11:50:54
0
yûñg bîllîøñz :
abeg make Nigeria school teachers no see this maths ooo
2026-08-24 15:25:19
4
Joe :
I agree with you
2026-08-24 09:46:47
2
ina cago :
I don't understand
2026-08-24 18:49:50
5
. :
There's always someone who checks the comments, but never writes. How are you my friend?
2026-08-25 02:38:28
24
☆Morata☆ :
Qui n'as rien compris comme moi🤯
2026-08-23 20:11:47
73
shojib🧃 :
x + 79 - x ² = x + 7, так что x = 1 и x = -2 V = PL112 (9-x2) ² - (x + 7) 2dx V = PL12 (x4-18 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x ² = x + 7, так что x = 1 и = - 2 x = = = = =
V = PL12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x ² = x + 7 So x = -2 V = PL112 (9-x2) ² - (x + 7) 2x V = PI12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x ² = x + 7 So x = 1 и x ² = PL112 (9-x2) - (x + 7) 2x
V = PL12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x ² = x + 7 So x = 1 и x = -2 V = PL112 (9-x2) ² - (x + 7) 2x V = PI12 (x4-18x ² + 81 x dx + 14x + 49) dx v = 12 = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x ² = x + 7, so x = 1 и x ² = PL112 (9-x2) - (x + 7) 2dx
V = PL12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x ² = x + 7 So x = 1 и x = -2 V = PL112 (9-x2) ² - (x + 7) 2dx V = PI12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = 79x ² = x 7 x x x x x = 1 x x = 2 x2 x x x v = x x 2 x x x x x x x x x x x x x x x x 14x + 32) dx19 V = x [-x-12 y = x + 79 x + 7 So x = 1 и x = -2 В = JP112 (9-x2) ² - (x + 7) 2x
V = PL12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x ² = x + 7 So x = 1 и x = -2 V = PL112 (9-x2) ² - (x + 7) 2x V = PI12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 9 - x При условии y = x + 79 - x ² = x + 7, so x = 1 и x = -2 V = PL112 (9-x2) - (x + 7) 2dx V = PL12 (x4-18x ² + 81) - (x + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x ² = x + 7, так что x = 1 и = - 2 x = = = = = = =
V = PL12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x ² = x + 7 So x = -2 V = PL112 (9-x2) ² - (x + 7) 2x V = PI12 (x4-18x ² + 81) - (x ² + 14x + 49) dx V = pi / 12 (x4 - 19x
2026-08-23 18:29:19
21
4TK :
1+1=2 15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 84) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) as you know 9 - x² produces y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7)= IS 134=raised to 15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = 3
2026-08-24 14:17:41
13
SADExGOATz7 :
bro you are a dangerous teacher
2026-08-24 22:11:37
7
user87418753465830 :
we can't divide by 0
3-3 equal 0 so your resonating in not correct.
2026-08-23 15:41:28
55
Genius :
0/0 n’existe pas en maths
2026-08-24 01:37:05
7
abdi8_788 :
2026-08-17 15:21:42
7
khahliso :
bro 1+1=2
2026-08-02 18:08:51
5
Prince mlk :
On peut simplifier un facteur commun seulement s’il est non nul. Ici, le facteur commun vaut zéro. Donc ces faux mon ami
2026-08-23 22:12:45
6
General DK :
so 1+1+1=2 😌
2026-08-25 03:02:52
0
bubbee diramaa :
inshot bro
2026-08-24 14:43:51
1
Brave :
intelligence
2026-07-31 14:28:32
1
Mahjoub :
What
2026-08-23 08:26:14
1
MISTERLEWIS 🪼 :
la femme que mon voisin a épousé ne me plaît pas
2026-08-23 21:10:58
2
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