If you set x=0 you get y^8 = 1. From the you get the y intercepts as y=+-1, which leaves only c and d as those are the only intercepts equidistant from the origine. From there you notice that y has two terms that can be negative, y and y^3 whilst x has none. This means that, given that the lhs must be equal to 1, the curve must be sloping downwards, so that the negative y values can cancel out the positive x and positive y values, unless the lhs would quickly become >1, leaving only c
2026-08-08 15:56:37
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p 😵💫 :
You can spot that the function cannot be increasing for x>0 and y>0 as all terms on LHS are positive, so can only be c
2026-08-08 15:29:27
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Lewis :
2026-09-06 21:06:00
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Dav1d_e :
🥰🥰🥰
2026-08-08 10:59:31
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