@boxcy_: How to solve the exponential equation 6^(x+5) = 5^(x+5) using essential math rules. First, we split the exponents on both sides using the product rule. Next, we rearrange the equation by grouping the variable terms on the left and the constant terms on the right. After combining the fractions, we flip the right side using a negative exponent so both sides share the exact same base of 6/5. Once the bases match, we simply equate the powers to solve for x = -5. #math #mathematics #mathtok #matematika #mathtrick

Boxcy
Boxcy
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Saturday 08 August 2026 10:11:41 GMT
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fatmakhatab200
Fatma Khatab :
6=2 x+5=0 x=-5
2026-08-19 06:50:30
0
blixx4rd
Kiritsuu_0 :
finally thing i can understand
2026-08-17 13:13:41
0
az_l070
𐌀ⱿⱿ_𐌋 :
Fyp think I’m smart🫩
2026-08-09 04:20:06
4354
ahmed910uibsgogeta
Blue Boy 💤🐋 :
the powers are the same you can just move them
2026-08-18 18:56:22
0
ameer.a350
Ameer 🇮🇶 :
Just use logs💔
2026-08-09 06:55:25
1364
manus_570
MONKEY D LUFFY :
² + 𝟾𝟷) - (² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡+ 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗𝚌𝚎𝚜 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡 𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸𝚡𝟹-𝟽 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸 𝟿 - 𝚡² 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚇𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡 𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸𝚡𝟹-𝟽 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗𝚌𝚎𝚜 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝟿 - 𝚡² 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗𝚌𝚎𝚜 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡 𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸𝚡𝟹-𝟽 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-w)= 𝚡² 𝚍𝚊 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - 𝚡² 𝚍𝚊 𝚢 = 𝚡 + 𝟽𝟿+&(168)+(6)-56=?² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗
2026-08-13 16:27:11
23
concac7295
👍 :
Tôi phải làm gì với thông tin này?
2026-08-11 05:57:58
160
yudss.real
Yudss Real :
intinya pahami jangan hafalin
2026-08-09 15:56:01
357
qqii.lock
QqIi Lock :
Эх, а я раньше все как орешки щелкала, сейчас все забыла...
2026-08-09 06:47:39
230
georgiconmilpies
Georgiconmilpies :
ala me volo la cabeza algo simple xd
2026-08-16 22:46:15
6
gege_df811
ffffffffd :
tinggal x + 5 = 0 x = -5 selesai
2026-08-15 02:20:26
27
nghuykhung
KneeMo :
a^0=1
2026-08-09 14:12:54
73
y0diee
nastya :
угадать легче
2026-08-18 06:53:04
5
trong.l053
Trong Lê :
cần gì phải phức tạp lên vậy, cứ nhớ bất kì số tự nhiên nào mũ 0 đều bằng 1 là được.
2026-08-12 10:56:14
8
user2633554482331
Пельменик :
А можно было легче же
2026-08-10 10:28:23
45
edenk1te
Edenkite :
Why aren’t we using logs?😭
2026-08-10 21:56:15
12
iatemymathteacher0
iatemymathteacher :
is this method also correct? 6^x+5 = 5^x+5 6^x+5 - 5^x+5=0 x+5(6-5)=0 x+5=0 x=-5 asking for a friend...🙃
2026-08-12 18:15:43
12
ice.cream_coklat
Ice.Cream_Coklat :
kalau basis beda tapi pangkat sama artinya x+5=0→x=-5
2026-08-09 01:43:57
17
g1nger.tea
g1nger :
это все понятно, но при чем тут Игнат🤨
2026-08-12 14:31:48
5
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