@boxcy_: How to solve the exponential equation 6^(x+5) = 5^(x+5) using essential math rules. First, we split the exponents on both sides using the product rule. Next, we rearrange the equation by grouping the variable terms on the left and the constant terms on the right. After combining the fractions, we flip the right side using a negative exponent so both sides share the exact same base of 6/5. Once the bases match, we simply equate the powers to solve for x = -5. #math #mathematics #mathtok #matematika #mathtrick
Boxcy
Region: ID
Saturday 08 August 2026 10:11:41 GMT
Music
Download
Comments
Fatma Khatab :
6=2
x+5=0
x=-5
2026-08-19 06:50:30
0
Kiritsuu_0 :
finally thing i can understand
2026-08-17 13:13:41
0
𐌀ⱿⱿ_𐌋 :
Fyp think I’m smart
2026-08-09 04:20:06
4354
Blue Boy 💤🐋 :
the powers are the same you can just move them
2026-08-18 18:56:22
0
Ameer 🇮🇶 :
Just use logs💔
2026-08-09 06:55:25
1364
MONKEY D LUFFY :
² + 𝟾𝟷) - (² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡+ 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗𝚌𝚎𝚜 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡
𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡 𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸𝚡𝟹-𝟽 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸 𝟿 - 𝚡² 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚇𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡
𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡 𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸𝚡𝟹-𝟽 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗𝚌𝚎𝚜 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝟿 - 𝚡² 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡 𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗𝚌𝚎𝚜 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - (𝚡 + 𝟽) 𝟸𝚍𝚡
𝚅 = π𝟷𝟸 (𝚡𝟺-𝟷𝟾𝚡² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡 𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸𝚡𝟹-𝟽 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-w)= 𝚡² 𝚍𝚊 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝚡 = 𝟷 𝚢 𝚡 = -𝟸 𝚅 = π𝟷𝟷𝟸 (𝟿-𝚡𝟸) ² - 𝚡² 𝚍𝚊 𝚢 = 𝚡 + 𝟽𝟿+&(168)+(6)-56=?² + 𝟾𝟷) - (𝚡² + 𝟷𝟺𝚡 + 𝟺𝟿) 𝚍𝚡 𝚅 = 𝚙𝚒 / 𝟷𝟸 (𝚡𝟺 - 𝟷𝟿𝚡𝟸 - 𝟷𝟺𝚡 + 𝟹𝟸) 𝚍𝚡𝟷𝟿 𝚅 = 𝚡 [-𝚡-𝟷𝟸 𝚢 = 𝚡 + 𝟽𝟿 - 𝚡² = 𝚡 + 𝟽 𝙴𝚗𝚝𝚘𝚗
2026-08-13 16:27:11
23
👍 :
Tôi phải làm gì với thông tin này?
2026-08-11 05:57:58
160
Yudss Real :
intinya pahami jangan hafalin
2026-08-09 15:56:01
357
QqIi Lock :
Эх, а я раньше все как орешки щелкала, сейчас все забыла...
2026-08-09 06:47:39
230
Georgiconmilpies :
ala me volo la cabeza algo simple xd
2026-08-16 22:46:15
6
ffffffffd :
tinggal
x + 5 = 0
x = -5
selesai
2026-08-15 02:20:26
27
KneeMo :
a^0=1
2026-08-09 14:12:54
73
nastya :
угадать легче
2026-08-18 06:53:04
5
Trong Lê :
cần gì phải phức tạp lên vậy, cứ nhớ bất kì số tự nhiên nào mũ 0 đều bằng 1 là được.
2026-08-12 10:56:14
8
Пельменик :
А можно было легче же
2026-08-10 10:28:23
45
Edenkite :
Why aren’t we using logs?😭
2026-08-10 21:56:15
12
iatemymathteacher :
is this method also correct?
6^x+5 = 5^x+5
6^x+5 - 5^x+5=0
x+5(6-5)=0
x+5=0
x=-5
asking for a friend...🙃
2026-08-12 18:15:43
12
Ice.Cream_Coklat :
kalau basis beda tapi pangkat sama artinya x+5=0→x=-5
2026-08-09 01:43:57
17
g1nger :
это все понятно, но при чем тут Игнат🤨
2026-08-12 14:31:48
5
To see more videos from user @boxcy_, please go to the Tikwm
homepage.
© 2021-2026 TikWM. All rights reserved.