@testandtutor: Solve the equationto find a,b #math #maths #mathematics #education #problemsolving #equation #maththinking

PS_Tik_Tok :

I love this method.

syamsoul :

a=3x, b+9=4x, b=4x-9, so 3x+4x-9=68, 7x=77, x=11, therefore a=33, b=35

ZouZoey :

b+a over 9 ?????

build different :

4a=3(77-a) =>4a=231-3a =>7a=231 =>a=33 =>b=68-33=36

Ahioatea :

I've calculated using a different method. But yours is much less tedious and at the same time a whole lot smarter. Thank you for the lesson!!!🥰

concept :

Ismail Mulla :

a=33 b=35

J B :

cute

Kagiso Phatlalalo :

Thanks Teacher

Max :

Wowwww😏!

Dmo :

very clear!!!

Rüfət 227 :

33 35

I am Groot :

I don't understand a shit

Rayar Rayar :

💔💔💔

Acerthorn :

@Braxton Comer

user1781185039048 :

🥰🥰🥰

mk nat :

😅😅😅

Tanyaradzwa Matobira :

❤️❤️❤️❤️

Know Everything :

🥰🥰🥰

TARIK EL3AJMAWI :

a + b = 68 {{ a = 68 - b --------------------- 68 - b / b + 9 = 3 / 4 4 (68 - b) = 3 ( b + 9 ) 272 - 4 b = 3 b + 27 - 4 b - 3 b = 27 - 272 - 7 b = - 245 b = 245 / 7 b = 35 ---------------------- a + 35 = 68 a = 68 - 35 a = 33 ((( a = 33 ; b =35 )))

Agustín Montero :

a+b=68 a/(b+9)=3/4 __ a+b=68 4a=3b+27__ a+b=68 4a-3b=27 __ 3a+3b=204 4a-3b= 27 __ 7a=231 a=33; b=68-33=35

MathCha :

So good 😊 may also try: if (A/3) = Z; 3Z = A; and A+B = 68 then 3Z + B = 68 and: reciprocal (B+9)/A = 4/3; then B+9 = 4Z; B = 4Z - 9; so: 3Z+4Z-9 = 68; 7Z = 68+9 = 77; Z = 11. 3(11) + B = 68; B = 68 - 33 = 35