Scientia
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Sunday 23 August 2026 00:05:11 GMT
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I’m In Your Walls :
Obv the left because it’s an approximation for e
2026-08-23 12:54:34
3
Engr Zia.Khan :
e
2026-08-23 00:46:28
16
Emanuta :
1.01¹⁰⁰ grows by at least 1 percent per exponent so 1.01 > 2
2026-08-23 07:32:26
62
Aries Chen :
1/1.01^100＜1/2，so 1.01^100＞2
2026-08-23 07:06:48
1
Primfaya :
hell 1.007^100 is more than 2
2026-08-23 14:39:24
2
Colius :
My main thought process was 1.01 because I know that 1.10^n>2 when n>7 so 1.01^n>2 when n>70.
2026-08-23 16:35:27
3
marxslop :
(1+1/100)^100 ≈ e ≈ 2.71 > 2
2026-08-23 21:15:29
0
Purevdorj :
1.01 > 1.01^100
2026-08-23 01:41:41
1
sol :
close to e=2.718.....👍
2026-08-23 16:13:16
1
Alex K. :
(1+0.01)^100=1+100×0.01+...=2+...>2 q.e.d.
2026-08-23 09:40:25
2
Neologist :
Think about this as an interest rate of 1 % per period. After 100 periods it has doubled therefore equals 2. As compound interest has to be added as well it“s clearly greater than 2.
2026-08-23 05:34:20
4
tyvocool :
using logarithm is very simple
2026-08-23 12:43:32
1
Hello you :
(1+1/n)^n <(1+1/n+1)^ (n+1) < e < (1+1/n) ^ (n+1)
2026-08-23 06:22:24
4
L043.6 :
e
2026-08-23 13:18:50
1
Frank :
If growth was linear both would be equal because 100*0.01=1 and 1+100*0.01=2 for x=2 we have 1+2*0.01=1.02 in case of linear growth and 1.01^2=1.0201 in case of exponential growth, seeing that exponential growth is faster than linear. so the left side is greater.😉
2026-08-23 05:51:42
3
Alexa 🫶🏼✨ :
3
2026-08-23 13:50:30
1
Jörg. :
@MathemaTrick Bitte mal auf Deutsch
2026-08-23 08:42:35
1
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