@pitochk: Today, LEDs are everywhere - in our phones, cars, medical equipment, streetlights, screens, and homes. They have become so ordinary that it is easy to forget how long it took us to get here. The first practical LEDs appeared in the 1960s. Red came first, followed by green and other colors. But for decades, one important piece was missing: a bright and efficient blue LED. Creating blue light was much more difficult. It required semiconductor materials capable of producing higher-energy photons. Gallium nitride (GaN) was a promising candidate, but growing high-quality crystals and making efficient devices from it remained an enormous challenge. It took decades of research before Isamu Akasaki, Hiroshi Amano, and Shuji Nakamura helped make efficient blue LEDs a reality - work that earned them the 2014 Nobel Prize in Physics. And blue changed everything. Red + green + blue made modern full-color LED displays possible. Blue LEDs combined with phosphors also opened the way to bright, efficient white lighting. The result is a technology that uses far less energy, lasts much longer, and has helped make efficient lighting accessible around the world. Sometimes the technologies that transform our lives don’t look impressive at all. Sometimes, they are just a tiny point of blue light. #LED #Technology #edit #Physics #Engineering
pitochk
Region: PL
Monday 24 August 2026 10:51:52 GMT
4738774
553026
2372
32899
Music
Download
Comments
user35429488544 :
Story of led
2026-08-24 15:40:19
43304
ZFR :
the blue light was actually tge hardest to make
2026-08-24 10:53:59
9463
𝗞𝗲𝘅𝗧𝘇𝘆 :
school ❌
tiktok ✅
2026-08-24 15:45:16
6975
AR7_ :
Impossible ?
2026-08-26 03:42:06
1018
zukoo the larper :
"but blue was impossible"
2026-08-26 06:48:50
1719
Emily :
Can you teach me to make this bro
2026-10-08 07:24:31
0
Eliott :
2026:
flying cars ❌
led edit ✅
2026-08-25 10:12:12
839
Roberto Santiago Her :
15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 84) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) as you know 9 - x² produces y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x [-x-12x3-7 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14X + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7)= IS 134=raised to 15 x + 79 - x² = x + 7 So x = 1 and x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) if V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x [-x-12 y = x + 79 - x² = x + 7 So x = 1 and x <562) = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (1+1=2😏😏😏😏
2026-08-28 02:39:15
5
Zinn[GD] :
no funciona,
lo intente y me explotó el microondas
2026-08-24 22:29:32
130
Michealll :
But blue was almost impossible to make
2026-08-24 10:55:36
2549
Nizam☑️𝕏 :
Rumus kecepatan cahaya dalam ruang hampa adalah \(c = 3 \times 10^8 \text{ m/s}\) atau tepatnya \(299.792.458 \text{ meter per detik}\). Simbol \(c\) berasal dari kata Latin celeritas yang berarti kecepatan.Kecepatan dalam Medium Lain:Ketika cahaya melewati medium selain ruang hampa (seperti air atau kaca), kecepatannya melambat dan dihitung dengan rumus:\(v=\frac{c}{n}\)\(v\) = kecepatan cahaya dalam medium\(c\) = kecepatan cahaya dalam ruang hampa (\(3 \times 10^8 \text{ m/s}\))\(n\) = indeks bias medium tersebutHubungan dengan Panjang Gelombang dan Frekuensi:Sebagai gelombang elektromagnetik, kecepatan cahaya juga memenuhi rumus gelombang umum:\(c=\lambda \times f\)\(\lambda \) = panjang gelombang (meter)\(f\) = frekuensi (Hz)Kesetaraan Massa dan Energi (Teori Relativitas Einstein):Dalam rumus terkenal \(E = mc^2\), huruf \(c\) digunakan sebagai konstanta kecepatan cahaya untuk menghitung besar energi (\(E\)) yang setara dengan suatu massa (\(m\)).
2026-09-26 03:33:56
13
Juli💫🌸 :
amo estoy videos.. me haces sentir inteligente
2026-10-01 17:40:08
44
𝓚𝓮𝓷˚.🎀༘⋆ :
School ❌ TikTok ✅
2026-10-08 08:24:13
0
Yêu NTNH :
Cái đèn led xanh dương chế tạo lâu vl
2026-09-18 07:22:08
61
🤯🤯🤯 :
led màu xanh từng bất khả thi đấy💀
2026-08-25 09:03:14
6
soundwave_superior74 :
Por que en estos edits siempre ponen a la mujer? Como tal está bien,pero también existe el hombre :v
2026-09-09 07:51:33
8
꧁🌅𝙎𝙪𝙣𝙨𝙚𝙩-𝙃𝙞𝙡𝙡🌄꧂ :
for you best editer🔥🔥🔥👍
2026-09-13 01:06:23
5
(chan_t_đê) :
Nhanh thế học giỏi cũng chả hiểu đc gì
2026-08-25 02:40:53
42
Ken👁️🗨️ :
tiếng ah v mà t hiểu vcl
2026-08-25 03:49:04
12
Gỗ 1 vỗ :
This is the first thing that came to my mind.
2026-08-26 12:19:43
5
JK :
but blue was almost impossible to make
2026-08-24 12:11:26
406
🇻🇳 :
15 x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. Nếu V = pi / 12 (x4 - 19x2 - 14x + 32) dx19, thì V = x [-x-12. y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 84) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19. V = x [-x-12x3-7. y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19. V = x [-x-12. y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19. V = x [-x-12x3-7. y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) như bạn biết, 9 - x² cho y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) dx19. V = x [-x-12. y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19. V = x [-x-12x3-7. y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) như bạn biết, 9 - x² cho y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) dx19. V = x [-x-12. y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19. V = x [-x-12x3-7. y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) như bạn biết, 9 - x² cho y = x + 79 - x² = x + 7 nên x = 1 và x = -2. V = π112 (9-x2)² - (x + 7)² dx. V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx. V = pi / 12 (x4 - 19x2 - 14x + 32) dx19. V = x [-x-12. y = x + 79 - 4
2026-08-24 12:47:16
12
To see more videos from user @pitochk, please go to the Tikwm
homepage.