Wade :
you people claiming the earth is flat cant show any evidence. here is something to consider August 26, 2026 at 11:00 AM in Oxford, PA / 8:00 AM in San Francisco, the Sun’s direction is approximately:
Location
Elevation
Azimuth
Oxford, PA
49.39°
127.97°
Candlestick Park, CA
15.84°
89.16°
Using a 4,000-mile-high Sun ( Science with Freddy's claim not mine) on the common north-pole-centered flat-Earth map, and keeping the same instant — 11:00 AM in Oxford / 8:00 AM in San Francisco on August 26, 2026 — the Sun would be directly over roughly 10.65° N, 44.45° W at that moment. NOAA defines solar elevation as the angle above the horizon and azimuth clockwise from north.On that flat map, the horizontal distances from the observers to the point beneath the Sun work out to about:
Oxford: 3,109 miles
Candlestick Park: 5,902 miles
For a Sun height of miles, the predicted elevation is θ = tan⁻¹(h/d) So the flat-Earth model predicts:
Oxford PA 52.1° San Francisco 34.1°
Candlestick Park: 5,902 miles
For a Sun height h= 4000 miles predicted elevation is
Oxford, PA
52.1° globe
49.4° flat earth
Candlestick Park, CA
34.1° globe
15.8 Flatearth
Oxford comes fairly close, but San Francisco is off by about 18°.
So one 4,000-mile Sun cannot match both simultaneous observations using that flat-Earth geometry. If we adjust the Sun height until San Francisco matches 15.8°, then Oxford will no longer match. So the same Sun, at the same instant, would have to be about 3,627 miles high according to Oxford, but only 1,670 miles high according to San Francisco.
2026-08-29 17:46:21