Think Daily
Region: SA
Saturday 12 September 2026 17:03:31 GMT
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idriss_ben_romdhane :
The second one could be proved directly using the formula for a^n - b^n
2026-09-12 18:29:31
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Tanya :
[Heartwarming][Red heart][Red heart][Red heart]
2026-09-13 11:18:30
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Maro :
🥰🥰🥰
2026-09-12 23:00:41
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nosequenombreponerme :
😂😂😂
2026-09-12 17:24:04
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Kei :
For the first one: Assume we have bars lined up like a triangle, we all know that the nth odd number is 2n - 1, so we get (1, 3, 5, 7, ...). Now we have a staircase made of the bars, it has a width of n and height of 2n - 1. Copy the whole staircase then rotate it by 180° and add 1 to the height, so now we have a rectangle with a width of n and height of 2n. To get the sum of the first n odd numbers, we will get half the area of the rectangle which is n(2n) / 2, now simplify: n(2n) / 2 2n² / 2 n² So it's now proven using geometry.
2026-09-14 10:14:45
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