mathscribbles
Region: US
Monday 14 September 2026 19:30:27 GMT
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sleeping tiger :
Use residual theorem which is much more general and you don't have to remember a very special trick like Glasser theorem. The result is simpler too. pi(sqrt(2)-1)/2.
2026-09-14 22:41:26
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1&$(( :
Do you think you could solve this? It’s not actually that bad…
2026-09-16 14:36:31
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The Mathmagician :
Thank you for this, brother.
2026-09-15 12:40:04
1
Dr. Runner :
we may make use if the following: \frac{x^2}{x^4+3x^2+2} = \frac{2}{x^2+2} - \frac{1}{x^2+1}
2026-09-14 20:45:15
0
to the grave :
2026-09-14 19:45:49
0
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