Marcus
Region: GB
Thursday 17 September 2026 15:04:21 GMT
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Pete H61 :
x²-9x+ 20 is necessarily even for all integers x
2026-09-17 18:03:06
199
Jurriaan de Greeuw :
can you plot it in Desmos?
2026-09-19 07:20:05
0
k2ted :
How did you know there are five solutions?
2026-09-18 05:25:01
18
Iulian Hodorog :
How did you know there must be 5 solutions?
2026-09-18 23:15:11
5
dennisr81 :
Are there any complex solutions?
2026-09-17 21:04:04
13
Clio :
Technically you should check that neither of the solutions that make the exponent 0 also make the base 0, since 0^0=1 is controversial.
2026-09-18 02:46:45
7
yutanakamura866 :
he's still not showing that those solutions are all of it.
2026-09-18 18:48:57
2
jappie :
how about 0^0 where x^2 -5x+5 = (x-5)(x-4)?
2026-09-17 22:19:11
5
jim :
Excellently explained at a good speed and without unnecessary extra working out.
2026-09-17 19:33:31
264
Matty Melt :
how do you know there are 5 solutions?
2026-09-18 05:10:04
0
Mihaś Gareza :
The last 2 "solutions" is out of domain
2026-09-18 13:10:39
0
Svruhchovek :
this was beautiful yo
2026-09-18 17:30:17
15
🇬🇾 Ꝉմçìժ Ꭰɾҽąʍҽɾ 🇬🇾 :
ELEGANT
2026-09-18 05:03:31
0
SoTiredOfTheSpin :
How do you know, right off, there are 5 solutions?
2026-09-18 12:50:22
0
Alice ♿ 🏳️⚧️ :
you need to make sure you don't end up with 0⁰ though for the first 2 solutions
2026-09-18 05:27:07
0
Luke :
Either the exponent is 0, number is 1 or both are 1 and then solve for each scenario
2026-09-17 20:55:32
20
James Kitchen :
you can also find these with ln btw, at least for the first 4. it's the same process
2026-09-17 15:54:01
16
BrunoSantanna015 :
In the first two solutions shown in the video, you forgot to check whether they would result in the indeterminate form 0^0. They don't, but you didn't check.
2026-09-18 21:33:18
1
Wqi0o0ipW :
Kinda forgot about (-1)^²ⁿ, had to think for a couple minutes :)
2026-09-17 19:05:43
7
dennisr81 :
Your argument only holds for polynomials. But this function isn't one.
2026-09-18 06:04:15
0
Gautham :
0 to the power of 0 is also one so cant you just set both the exponent and the base to 0 and solve for x?
2026-09-17 15:22:40
1
pomegranate :
X=4 should be discarded
2026-09-17 22:30:53
0
PrinXx💣💃 :
How do you know there are 5 solutions to begin with?
2026-09-17 17:29:57
0
Machin Shin :
you probably should have also checked to make sure x=5 didn't result in a base of 0 (an indeterminate form). it doesn't, but it's good to make sure.
2026-09-18 05:59:38
4
KHWDFBL :
There are 7 real solutions: 1, 2, 3, 4, 5, (9-√17)/2 , (9-√33)/2 There are also infinitely many complex solutions if we interpret the power using the principal complex logarithm. 😎
2026-09-18 19:10:50
2
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