Physics for +2 level
Region: NP
Sunday 20 September 2026 04:07:40 GMT
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tapsa turri :
70/2=35kg. 35/2=17,5kg 17,5kg/cos(30)=20,2kg force depends on gravity..in moon need less force..
2026-09-20 04:18:48
11
Domino :
F= 70/4/cos(30⁰)*9,81N ≈ 198,23N
2026-09-21 20:43:13
1
Charliebfarlie :
Interesting one because the pulley wouldn’t be in that place in real life, it would be over to the right and the resultant would be at 15 deg to vertical
2026-09-20 22:14:42
2
BigJer25 :
The horses name was Friday!
2026-09-21 23:20:09
1
Moraka :
F(cos 30+1)=35. F=35/(cos 30+1)=18.75 kg approx.
2026-09-20 06:23:27
2
Mark Hanoi :
Both sides of pull is 35kg. So both sides of next pulley is 17,5kg. Devide by cos(30deg) is 20,2kg, which is about 200N
2026-09-20 14:52:11
4
goczuyyl :
it depends. does this happen on earth? on the moon or in the ISS?
2026-09-20 13:24:27
0
Leppis73 :
39,13 kg
2026-09-20 11:59:45
0
Carlo :
20,23kgf. 198,45 N .
2026-09-20 09:13:00
1
arthurcamciuc :
the horizontal component of F must be cancelled by other force so this cannot be the equilibrium position
2026-09-20 06:36:27
3
Roxy :
17.5
2026-09-20 04:31:43
2
adamcollins237 :
1/cos 30deg x 70/4
2026-09-20 09:31:16
1
Riza :
198 N
2026-09-20 06:32:44
3
Il_Prof_Meccatronico :
35
2026-09-20 06:29:10
0
bankraeuber0815 :
Die erforderliche Kraft beträgt ca. 343,35 Newton, um die Last im Gleichgewicht zu halten (unter der Annahme einer Standard-Erdbeschleunigung von 9,81m/s).
2026-09-20 10:54:34
0
alexabdullahi1 :
35/2 /cos30
2026-09-20 15:47:13
1
Mariusz Haśkiewicz :
18,75 kg. 187,5N
2026-09-21 12:30:10
0
AI Pawsgination :
F18.76 Kg
2026-09-20 14:37:33
1
Wowo :
35 kilo
2026-09-24 13:59:43
0
user7103334415 :
plus, you are saying it is held at rest, that means it isn't moving......
2026-09-21 04:15:10
0
AK :
17.5 kg
2026-09-21 15:39:32
0
Ma Nepali :
Assuming g= 10m/s^2 ==》F= 350÷cos 30° =404.15 N
2026-09-23 05:20:07
0
ghenamahmed :
20,23 kg
2026-09-21 11:34:20
0
Rudy :
20,20
2026-09-21 19:56:42
0
user31286716540108 :
70/1,73
2026-09-20 08:06:27
0
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