𝙍𝘼 𝙁𝙄 -𝐕3
Region: BD
Saturday 03 October 2026 07:04:43 GMT
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EMON_CHOWDHURY :
চেন স্পকেট শেষ🙂🤌
2026-10-03 08:37:14
223
🌚 𝙈𝙐𝙎𝘼 𝙑𝘼𝙄 🌚 :
তখন জদি বাইক নষ্ট হয়ে জেতো 🙃🙏
2026-10-03 08:14:13
500
ᎫЇᎻᎪƊ 🀄 :
story ta kemon😅
2026-10-04 03:28:25
0
S E Y A M ‼️ :
Chain Sporket Somossa 🤣
2026-10-04 03:12:19
0
💗 T. 💗 Lijon Ahamed :
গানটা মনে হচ্ছে এখন পূর্ণতা পেলো 🤣🤣
2026-10-03 09:57:18
157
❤️🔥ɪᴛꜱ ᴍᴇ ʀᴏʜᴀɴ❤️🔥 :
[Cool][Pray]
2026-10-03 09:03:30
1
Prince Vegeta :
Ei video dekhle to jail a pure dibe 🙂
2026-10-03 16:01:59
1
–𝐘𝐨𝐔𝐫 ♡ 𝐌𝐢𝐌 🍒🧃 :
নোটিফিকেশন পাঠালে লাথি দিমু-!🙂🙏🏻
2026-10-03 11:44:38
47
Md Shamim reza :
এই টাইমে যদি বন্ধ হয়ে যেত গাড়িটা 🙏🙂
2026-10-03 08:50:28
39
Nᴀɪᴍᴀ ɪꜱʟᴀᴍ !🕊️ :
কেউ প্রেম করবা গো..!😫🫶
2026-10-03 14:50:58
3
ANGELA MUNNI🌚💋 :
কোথায় ছিলে Next...!?🙂
2026-10-03 10:27:24
16
▀𝒮ℋ𝒪ℋ𝒜𝒢🚫 :
ভাইয়া চেন আর ইসপকেট আছে কী😁
2026-10-03 09:15:30
14
Who is am! :
Today is my birthday ❤️🩹
2026-10-04 01:22:59
1
𓂃লক্ষী𓍯🌻🤍 :
𝐊𝐞𝐰 𝐆𝐫𝐮𝐨𝐩 𝐚 𝐚𝐝𝐝 𝐡𝐨𝐛𝐚_ ?🫶🌷
2026-10-03 11:09:20
7
🍭Choco🍭 :
মেয়ে হয়েও ছেলেদের উপর ক্রাস খাই😅
2026-10-04 03:06:03
1
—͞Mɪᴍ ꪇ༊ :
কেউ আমার সাথে ফ্রী ফায়ার খেলবা
2026-10-04 05:15:10
1
⃝👑~>ℜ𝔲𝔪𝔢𝖑♡🍺🥂🩹 :
তোমাদেরকে দেখেছিলাম ভাই ওই সময় পার্কের মধ্যে ছিলাম
2026-10-03 08:33:05
14
~𝐌𝐚𝐲๓🦢🪄 :
Kot🐸💔
2026-10-03 07:18:26
11
Mst.Mahi :
এটা তো কাটাখাল😁😁
2026-10-04 02:44:33
0
—✧𝐇𝐢𝐧𝐚𝐭𝐚ᥫ᭡_⋆⃝🦋 :
বাইক টা বন্ধ হয়ে গেলে তখন 😂🤣
2026-10-03 17:57:21
0
𝐑𝐈𝐃𝐄𝐑 𝐍𝐀𝐙𝐌𝐔𝐋 -_- :
কাহিনি বুঝলাম না 🙂
2026-10-03 12:34:12
2
sad🥹 boy 😔😮💨 :
এইটা না ঝিকরগাছা [Heartwarming]
2026-10-03 12:42:41
1
নুসরাত :
কেউ বন্ধু আমার হবে
2026-10-03 16:47:30
1
𝐌𝐢𝐫𝐚𝐣 🤍🇧🇩🇪🇺 :
2026-10-03 08:39:20
1
𝐎𝐧𝐥𝐲 𝐚𝐛𝐢𝐫 :
2026-10-03 08:52:52
1
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![CÔNG THỨC LƯỢNG GIÁC 1) Công thức cơ bản: sin²x+cos²x=1 tanx=sinx/cosx cotx=cosx/sinx tanx.cotx=1 tan²x+1=1/cos²x cot²x+1=1/sin²x sin(x+k2π)=sinx cos(x+k2π)=cosx tan(x+kπ)=tanx cot(x+kπ)=cotx 2)Hai góc liên quan đặc biệt: Đối: cos(-x)=cosx sin(-x)=-sinx tan(-x)=-tanx cot(-x)=-cotx Bù nhau: sin(π-x)=sinx cos(π-x)=-cosx tan(π-x)=-tanx cot(π-x)=-cotx Phụ nhau: cos(π/2-x)=sinx sin(π/2-x)=cosx tan(π/2-x)=cotx cot(π/2-x)=tanx Hơn nhau π: sin(x+π)=-sinx cos(x+π)=-cosx tan(x+π)=tanx cot(x+π)=cotx Hơn nhau π/2: sin(x+π/2)=cosx cos(x+π/2)=-sinx tan(x+π/2)=-cotx cot(x+π/2)=-tanx 3)Côngthứccộng: cos(x+y)=cosx.cosy-sinx.siny cos(x-y)=cosx.cosy+sinx.siny sin(x+y)=sinx.cosy+cosx.siny sin(x-y)=sinx.cosy-cosx.siny tan(x+y)=(tanx+tany)/(1-tanx.tany) tan(x-y)=(tanx-tany)/(1+tanx.tany) Hệ quả: tan(π/4+x)=(1+tanx)/(1-tanx) tan(π/4-x)=(1-tanx)/(1+tanx) Công thức nhân đôi: sin2x=2sinx.cosx cos2x=cos²x-sin²x=2cos²x-1=1-2sin²x tan2x=2tanx/(1-tan²x) Công thức nhân ba: cos3x=4cos³x-3cosx sin3x=3sinx-4sin³x Công thức hạ bậc: cos²x=(1+cos2x)/2 sin²x=(1-cos2x)/2 tan²x=(1-cos2x)/(1+cos2x) Đẳngthức: sin⁴x+cos⁴x=1-1/2sin²2x sin⁶x+cos⁶x=1-3/4sin²2x 4)Công thức biến đổi tích thành tổng: cosx.cosy=1/2[cos(x-y)+cos(x+y)] sinx.siny=1/2[cos(x-y)-cos(x+y)] sinx.cosy=1/2[sin(x-y)+sin(x+y)] cosx.siny=-1/2[sin(x-y)+sin(x+y)] 5)Công thức biến đổi tổng thành tích: cosx+cosy=2cos((x+y)/2)cos((x-y)/2) cosx-cosy=-2sin((x+y)/2)sin((x-y)/2) sinx+siny=2sin((x+y)/2)cos((x-y)/2) sinx-siny=2cos((x+y)/2)sin((x-y)/2) Hệ quả: sinx+cosx=√2.sin(x+π/4)=√2.cos(x-π/4) sinx-cosx=√2.sin(x-π/4)=-√2.cos(x+π/4) #congthucluonggiac #daumeoduoichuot #exsh #toan #matelliana](/video/cover/7691967933085502738.webp)
