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Electrical Calculation – Part 4 This image explains 10 important electrical calculations, including energy cost, load current, voltage drop, cable losses, fuse rating, conductor size, efficiency, power factor correction, and earth resistance. 1. Energy Cost Formula: Cost = Energy × Rate Where: Energy = Electrical energy consumed in kilowatt-hours (kWh). Rate = Cost per kWh. Example: Load = 1.5 kW Operating time = 6 hours Electricity rate = Rs. 8 per unit Energy consumed = 1.5 × 6 = 9 kWh Total cost = 9 × 8 = Rs. 72 One unit of electricity is equal to 1 kWh. 2. Load Current (Single Phase) This formula calculates the current required by a single-phase electrical load. Formula: Where: I = Current in amperes (A). P = Power in watts (W). V = Voltage in volts (V). PF = Power factor. Example: Power = 2000 W Voltage = 230 V Power factor = 0.8 Answer: 10.87 A This formula is useful for calculating the current drawn by motors and other AC electrical loads when the power factor is known. 3. Load Current (Three Phase) This formula calculates the current in a balanced three-phase electrical system. Formula: Where: I = Line current in amperes. P = Total three-phase power in watts. � = Line-to-line voltage. PF = Power factor. √3 ≈ 1.732. Example: Power = 10,000 W Line voltage = 400 V Power factor = 0.8 Answer: 18.04 A This calculation is commonly used for three-phase motors, industrial machinery, and other three-phase loads. 4. Voltage Drop Voltage drop is the reduction in voltage that occurs when current flows through a wire or conductor. Formula: Where: � = Voltage drop in volts. I = Current in amperes. R = Resistance in ohms. Example: Current = 10 A Resistance = 2 Ω Answer: 20 V The voltage drop in a real cable circuit depends on cable resistance and, for AC circuits, potentially cable reactance and power factor. In a two-wire circuit, the resistance of the complete current path must be considered. 5. Power Loss in Cable When current flows through a cable, some electrical energy is converted into heat. Formula: Where: � = Power loss in watts. I = Current in amperes. R = Resistance in ohms. Example: Current = 15 A Resistance = 0.5 Ω Answer: 112.5 W Higher current produces greater heating losses. This is why selecting the correct cable size is important. 6. Fuse Rating A fuse protects an electrical circuit by disconnecting the supply when excessive current flows. Formula shown in the image: Where: � = Calculated fuse rating. � = Load current. Example: Load current = 16 A Calculated value: 20 A Important: The 1.25 multiplier is not a universal fuse-sizing rule. The correct fuse rating depends on the applicable electrical code, load characteristics, conductor ampacity, and manufacturer's requirements. For a 16 A load, a 20 A fuse is not automatically suitable. 7. Conductor Size (Copper Wire) This calculation estimates the conductor's cross-sectional area based on current and an assumed current density. Formula: Where: A = Conductor cross-sectional area in mm². I = Current in amperes. J = Current density in A/mm². Example: Current = 20 A Assumed current density = 4 A/mm² Answer: 5 mm² This is a theoretical estimate, not a final cable-selection result. Actual cable sizing must account for insulation, installation method, ambient temperature, grouping with other cables, permissible voltage drop, and short-circuit protection. Select an appropriate standard cable size based on these factors. 8. Efficiency Efficiency tells us how much of the input power is converted into useful output power. Formula: Where: � = Efficiency in percent. � = Useful output power. � = Input power. Example: Output power = 4 kW Input power = 5 kW Answer: 80% This means the equipment delivers 80% of its input power as useful output power. The remaining 20% represents losses. This calculation is useful when studying motors, transformers, power supplies, and inverters. 9. Power Factor Correction Power factor correction reduces the reactive power drawn from the ##basicelectronics #ElectronicsExplained #ElectronicsEducation #foryou #CircuitDesign #
Electrical Calculation – Part 4 This image explains 10 important electrical calculations, including energy cost, load current, voltage drop, cable losses, fuse rating, conductor size, efficiency, power factor correction, and earth resistance. 1. Energy Cost Formula: Cost = Energy × Rate Where: Energy = Electrical energy consumed in kilowatt-hours (kWh). Rate = Cost per kWh. Example: Load = 1.5 kW Operating time = 6 hours Electricity rate = Rs. 8 per unit Energy consumed = 1.5 × 6 = 9 kWh Total cost = 9 × 8 = Rs. 72 One unit of electricity is equal to 1 kWh. 2. Load Current (Single Phase) This formula calculates the current required by a single-phase electrical load. Formula: Where: I = Current in amperes (A). P = Power in watts (W). V = Voltage in volts (V). PF = Power factor. Example: Power = 2000 W Voltage = 230 V Power factor = 0.8 Answer: 10.87 A This formula is useful for calculating the current drawn by motors and other AC electrical loads when the power factor is known. 3. Load Current (Three Phase) This formula calculates the current in a balanced three-phase electrical system. Formula: Where: I = Line current in amperes. P = Total three-phase power in watts. � = Line-to-line voltage. PF = Power factor. √3 ≈ 1.732. Example: Power = 10,000 W Line voltage = 400 V Power factor = 0.8 Answer: 18.04 A This calculation is commonly used for three-phase motors, industrial machinery, and other three-phase loads. 4. Voltage Drop Voltage drop is the reduction in voltage that occurs when current flows through a wire or conductor. Formula: Where: � = Voltage drop in volts. I = Current in amperes. R = Resistance in ohms. Example: Current = 10 A Resistance = 2 Ω Answer: 20 V The voltage drop in a real cable circuit depends on cable resistance and, for AC circuits, potentially cable reactance and power factor. In a two-wire circuit, the resistance of the complete current path must be considered. 5. Power Loss in Cable When current flows through a cable, some electrical energy is converted into heat. Formula: Where: � = Power loss in watts. I = Current in amperes. R = Resistance in ohms. Example: Current = 15 A Resistance = 0.5 Ω Answer: 112.5 W Higher current produces greater heating losses. This is why selecting the correct cable size is important. 6. Fuse Rating A fuse protects an electrical circuit by disconnecting the supply when excessive current flows. Formula shown in the image: Where: � = Calculated fuse rating. � = Load current. Example: Load current = 16 A Calculated value: 20 A Important: The 1.25 multiplier is not a universal fuse-sizing rule. The correct fuse rating depends on the applicable electrical code, load characteristics, conductor ampacity, and manufacturer's requirements. For a 16 A load, a 20 A fuse is not automatically suitable. 7. Conductor Size (Copper Wire) This calculation estimates the conductor's cross-sectional area based on current and an assumed current density. Formula: Where: A = Conductor cross-sectional area in mm². I = Current in amperes. J = Current density in A/mm². Example: Current = 20 A Assumed current density = 4 A/mm² Answer: 5 mm² This is a theoretical estimate, not a final cable-selection result. Actual cable sizing must account for insulation, installation method, ambient temperature, grouping with other cables, permissible voltage drop, and short-circuit protection. Select an appropriate standard cable size based on these factors. 8. Efficiency Efficiency tells us how much of the input power is converted into useful output power. Formula: Where: � = Efficiency in percent. � = Useful output power. � = Input power. Example: Output power = 4 kW Input power = 5 kW Answer: 80% This means the equipment delivers 80% of its input power as useful output power. The remaining 20% represents losses. This calculation is useful when studying motors, transformers, power supplies, and inverters. 9. Power Factor Correction Power factor correction reduces the reactive power drawn from the ##basicelectronics #ElectronicsExplained #ElectronicsEducation #foryou #CircuitDesign #
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Part 13 Free og for quote edits...❣️💦🌴🙏👑🇵🇬🌿#fyppppppppppppppppppppppp #morobeprovince💙💚💛 #menyamya #trend
Part 13 Free og for quote edits...❣️💦🌴🙏👑🇵🇬🌿#fyppppppppppppppppppppppp #morobeprovince💙💚💛 #menyamya #trend

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