@aztecanoticias: Una embestida más a la libertad de expresión se cocina en Palacio Nacional Bajo el pretexto de erradicar la violencia digital, buscan obligar a las redes sociales a tomar medidas adicionales a sus normas comunitarias. @luisamalcalde, Consejera Jurídica, afirma que obligarán a plataformas a retirar contenidos violentos, mientras que José Merino, Titular de la Agencia de Transformación Digital y Telecomunicaciones, admite que buscan ampliar la lista de publicaciones de riesgo. Con el pretexto de proteger, el @gobmx meterá las manos para decidir qué se publica, silenciando la crítica política y dando otro zarpazo de censura. El reporte de Agustín Rodríguez en #Hechos con Jaime Guerrero. #LibertadDeExpresión #CensuraDigital #México Libertad de expresión, violencia digital, redes sociales, censura, Gobierno federal, Palacio Nacional, normas comunitarias,

Azteca Noticias
Azteca Noticias
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Saturday 10 October 2026 05:55:00 GMT
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cristian_cercua
Cristian Cervantes :
ay ay ay, azteca está muy desesperado 😂😂😂
2026-10-10 06:05:07
1
papoi67g
$#@Geørgįńã?! :
primero
2026-10-10 05:57:37
0
elbajorojo
El Bajo Rojo :
no quieren quitar la violencia digital, quieren callar a los que criticamos al gobierno, así de claro
2026-10-10 08:00:25
0
michel.horocio
Michel HOrocio :
los padres deben hacer eso no el gobierno esto
2026-10-10 06:06:24
0
user107323282
... :
Es ilegal ser hermoso en México?
2026-10-10 06:48:38
0
melo06135
melo :
la.derecha jamás vuelva al.poder
2026-10-10 06:03:23
0
666abel0
꧁༒☬𝔸𝔹𝔼𝕃☬༒꧂ :
2026-10-10 06:49:25
0
bimbo.com1
EL MAPACHE 🦝 :
Buenas noches
2026-10-10 05:57:23
0
ivan_y_vienen5
XYNZ7 :
holaaa
2026-10-10 05:57:14
0
leonaversace1
LEONA VERSACE :
falso. falso falso
2026-10-10 06:00:55
0
william.snchez736
William Sánchez. Y💘 :
No mames nada les gusta que quieres q pongan a alguien mAtaNdO en el teléfono y también sabemos q ninguna aplicación ase su chamba por eso demandaron a meta
2026-10-10 06:05:20
0
armandovera333
ArmandoVera :
Esque tambien con lo que paso con cerimedo y la ultraderecha con golpes de redes sociales si esta cañón y mas cuando son dueños de granjas de bots para sacar a un gobierno en las elecciones. (deberían sacar un reportaje de lo que pasó en Bolivia con cerimedo y por que lo quieren liberar los gringos de la prisio) ah es tv azteca nunca pasaran eso.
2026-10-10 06:05:34
0
maaselcruk
MaaSelcruk :
No te creo bola de mentirosos!!!
2026-10-10 06:07:37
0
angelgaz77
angelgaz77 :
Viva la 4t 😍😍😍🇲🇽🇲🇽🇲🇽
2026-10-10 07:03:55
1
senyu0808
Sen Yusef :
😂😂😂😂
2026-10-10 07:19:12
0
javiervaldes58
javi :
😂😂😂
2026-10-10 06:28:26
0
filips.jimenez1
Filips Jimenez :
😂
2026-10-10 08:05:51
0
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REUPLOAD | #ukraine #usa #based #politics #trending Based! 🔥😙🇺🇸🇺🇦 American-Ukranian Brotherhood 🇺🇸 ❤️ 🇺🇦 LOVE ALL!! ❤️ Graham's number is an immense number that arose as an upper bound on the answer of a problem in the mathematical field of Ramsey theory. It is much larger than many other large numbers introduced as effective bounds in mathematics, such as Skewes's bound, which in turn is much larger than a googolplex. Graham's number is so large that the observable universe is far too small to contain its ordinary digital representation, assuming that each digit occupies one Planck volume. But even the number of digits in this digital representation of Graham's number would itself be a number so large that its digital representation cannot be represented in the observable universe. Nor even can the number of digits of that number—and so forth, for a number of times far exceeding the total number of Planck volumes in the observable universe. Thus, Graham's number cannot be expressed even by physical universe-scale power towers of the form  a b c ⋅ ⋅ ⋅ {\displaystyle a^{b^{c^{\cdot ^{\cdot ^{\cdot }}}}}}, even though Graham's number is indeed a power of three. However, Graham's number can be explicitly given by computable recursive formulas using Knuth's up-arrow notation or equivalent, as was done by Ronald Graham, the number's namesake. As there is a recursive formula to define it, it is much smaller than typical busy beaver numbers, the sequence of which grows faster than any computable sequence. Though too large to ever be computed in full, the sequence of digits of Graham's number can be computed explicitly via simple algorithms; the last 10 digits of Graham's number are ...2464195387.[1] Using Knuth's up-arrow notation, Graham's number is  g 64 {\displaystyle g_{64}},[2] where g n = { 3↑↑↑↑3,	 if  n=1  and 3 ↑ g n − 1 3,	 if  n≥2.  {\displaystyle g_{n}={\begin{cases}3\uparrow \uparrow \uparrow \uparrow 3,&{\text{if }}n=1{\text{ and}}\\3\uparrow ^{g_{n-1}}3,&{\text{if }}n\geq 2.\end{cases}}} Graham's number was used by Graham in conversations with popular science writer Martin Gardner as a simplified explanation of the upper bounds of the problem he was working on. In 1977, Gardner described the number in Scientific American, introducing it to the general public. At the time of its introduction, it was the largest specific positive integer ever to have been used in a published mathematical proof. The number was described in the 1980 Guinness Book of World Records, adding to its popular interest. Other specific integers (such as TREE(3)) known to be far larger than Graham's number have since appeared in many serious mathematical proofs, for example in connection with Harvey Friedman's various finite forms of Kruskal's theorem. Additionally, smaller upper bounds on the Ramsey theory problem from which Graham's number was derived have since been proven to be valid. Example of a 2-colored 3-dimensional cube containing one single-coloured 4-vertex coplanar complete subgraph. The subgraph is shown below the cube. This cube would contain no such subgraph if, for example, the bottom edge in the present subgraph were replaced by a blue edge – thus proving by counterexample that N* > 3. Graham's number is connected to the following problem in Ramsey theory: Connect each pair of geometric vertices of an n-dimensional hypercube to obtain a complete graph on 2n vertices. Colour each of the edges of this graph either red or blue. What is the smallest value of n for which every such colouring contains at least one single-coloured complete subgraph on four coplanar vertices? In 1971, Graham and Rothschild proved the Graham–Rothschild theorem on the Ramsey theory of parameter words, a special case of which shows that this problem has a solution N*. They bounded the value of N* by 6 ≤ N* ≤ N, with N being a large but explicitly defined number N = F 7 ( 12 ) = F ( F ( F ( F ( F ( F ( F ( 12 ) ) ) ) ) ) ) , {\displaystyle N=F^{7}(12)=F(F(F(F(F(F(F(12))))))),} where  F ( n ) = 2 ↑ n 3 {\displaystyle F(n)=2\
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