ᴀᴅᴠᴏᴄᴀᴛᴇ
Region: BY
Saturday 17 October 2026 16:09:10 GMT
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MILJENKO :
я смотрел, офигенное аниме
2026-10-17 17:15:49
32
Julian Trigger :
Блиииин, в первой серии он такой аура был 😫😫🤌. А потом пошел май Литтл пони. дружба это чудо и тд. миня никто не любил и тд
2026-10-17 17:35:12
101
макктрахер :
названіє
2026-10-17 17:20:44
3
corpse :
это чисто я в школе когда я злой, меня даже 11 классики пабедить не могут я их могаю шатаю так как я абсолют ещё я гуль один раз меня толпой били и у меня стали белые волосы
2026-10-18 10:28:47
0
Darkwolf_25 :
аниме:ветролом
2026-10-18 06:21:40
3
_ttshadow_1 :
"Пощади меня о великий господин"
2026-10-17 20:47:04
0
Gls🔞 :
гуль
2026-10-18 07:10:40
0
Pem :
я несколько раз пересматривал
2026-10-18 08:20:44
1
Krutysh :
😳😳😳
2026-10-18 07:08:52
0
To see more videos from user @mykogijeong, please go to the Tikwm
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![Graham’s number is one of the most insanely large finite numbers that has appeared in serious mathematics. It came from a problem in Ramsey theory, a branch of combinatorics. The crazy part is that we don't write Graham's number using ordinary powers like \(10^{100}\). We need Knuth's up-arrow notation. 1. Start with normal powers \[ 3\uparrow3 = 3^3 = 27 \] Two arrows mean repeated exponentiation: \[ 3\uparrow\uparrow3 =3^{3^3} =3^{27} =7,625,597,484,987 \] Already ~7.6 trillion. Three arrows are dramatically larger: \[ 3\uparrow\uparrow\uparrow3 \] This means you're repeatedly building power towers. Four arrows are even more extreme: \[ 3\uparrow\uparrow\uparrow\uparrow3 \] And this isn't even Graham's number yet. 2. The insane recursive part Define: \[ g_1=3\uparrow\uparrow\uparrow\uparrow3 \] Then: \[ g_2=3\uparrow^{g_1}3 \] Meaning: put \(g_1\) arrows between the two 3s. Then: \[ g_3=3\uparrow^{g_2}3 \] Now the number of arrows itself is \(g_2\). Keep doing this: \[ g_n=3\uparrow^{g_{n-1}}3 \] until: \[ \boxed{G=g_{64}} \] That \(G\) is Graham's number. 🤯 Why it's so huge Think of the progression: Exponentiation \[ 3^3 \] ↓ Power towers \[ 3\uparrow\uparrow3 \] ↓ Repeated power towers \[ 3\uparrow\uparrow\uparrow3 \] ↓ An even higher operation \[ 3\uparrow\uparrow\uparrow\uparrow3 \] ↓ Then Graham's construction says: > Take the enormous result and use it as the number of arrows. Then take that enormous result and use it as the number of arrows. Repeat this 64 times. So it's not simply](/video/cover/7695799630096829710.webp)
