@rody.editz0: 𝓘(α,β,s,λ) = limₙ→∞ Σₖ₌₁ⁿ [μ(k)·φ(k)/(kˢ·ln(k+1))] ∫₀∞ [x^(α−1)·e^(−βkx)·ln²(x+1)/(1−e^(−x))] dx + (1/2πi)∮Γ [e^(z²+λz)·Γ(z)·ζ(z)/(z⁴−αz²+βz+1)] dz + Σₙ₌₀∞ [(-1)ⁿ/(2n)!] · ∂²ⁿ/∂x²ⁿ [e^(−x²)·Σₘ₌₀∞ (xᵐ/m!)·∂ᵐu(x,y)/∂yᵐ] |ₓ₌₀,ᵧ₌₀ + det[∫₀¹ x^(i+j+α−1)·(ln x)²·e^(−βx)·J₀(λx) dx]ᵢ,ⱼ₌₁ᵐ + ∏ₚ≤ᴺ (1−p^(−s))^(−1) · exp(∫₋∞∞ [e^(−t²)·cos(ωt)·cosh(λt)/(1+t⁴)] dt) + Σₖ₌₁∞ [B₂ₖ/(2k)!]·(d²ᵏ/dx²ᵏ)[xˢ/(eˣ−1)]|ₓ₌₀ + ∫₀∞∫₀∞ [e^(−x²−y²)·sin(λxy)/(1+x²+y²)ˢ] dx dy + Σₙ₌₁∞ [1/nˢ]·∏ₖ₌₁ⁿ [1+λ/(k²+αk+β)] + limₘ→∞ det[Iᵢⱼ]ᵢ,ⱼ₌₁ᵐ + ∇·(∇u) − ∂²u/∂t² + ∫Ω [∇u·∇v + V(x)uv] dΩ = λ∫Ω uv dΩ + Σₙ₌₀∞ [(-1)ⁿ/(n!)]·∫₀∞ xⁿe^(−x²)·₂F₁(α,β;γ;−x) dx + ∮∂Ω [(∂u/∂n)·v − u·(∂v/∂n)] dS + limₕ→₀ [f(x+h)−2f(x)+f(x−h)]/h² + Σₚ prime [ln(p)/(pˢ−1)] + ∫₀¹ [ln(x)ln(1−x)/(1−x)] dx + Σₙ₌₁∞ [1/n²]·∫₀∞ e^(−nx)·sin(nx)/(1+x²) dx + tr(eᴬ) − det(A) + Σₖ₌₀∞ [(−λ)ᵏ/(k!)]·∫₀∞ tᵏe^(−αt²−βt) dt + ∫₋∞∞ [e^(−x²)·Hₙ(x)·Hₘ(x)] dx = 2ⁿn!√π·δₙₘ + Σₙ₌₁∞ [1/nˢ] + ∫₀∞ [x^(s−1)/(eˣ−1)] dx = Γ(s)ζ(s) + ∂²u/∂x² + ∂²u/∂y² + ∂²u/∂z² − (1/c²)∂²u/∂t² = 0 + limₙ→∞ ∏ₖ₌₁ⁿ [1+1/k]^(1/k) · e^(−1/k²) + Σₖ₌₁∞ [(-1)ᵏ⁺¹/k]·sin(kx) + ∫₀∞ [e^(−ax)−e^(−bx)]/x dx = ln(b/a) + Σₙ₌₀∞ [(−1)ⁿx²ⁿ/(2n)!] + ∮Γ dz/(zⁿ⁺¹) = 2πi·δₙ,₋₁ + det(AB)=det(A)det(B) + tr(AB)=tr(BA) + ∀ε>0 ∃δ>0: 0<|x−a|<δ ⇒ |f(x)−L|<ε + ∫₀¹∫₀¹ [xᵅyᵝ/(1−xy)] dx dy + Σₙ₌₁∞ [μ(n)/nˢ] = 1/ζ(s) + Γ(z)Γ(1−z)=π/sin(πz) + e^(iπ)+1=0 . . . #فوریو_نظری_به_حال_ما_کن #گمشو_برو_فوریو #فلاپ_نشوووو #فوریو_پاشم_بیام_جرت_بدم

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Wednesday 21 October 2026 08:50:38 GMT