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Thursday 05 November 2026 18:38:02 GMT
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NOLAIrish :
You said, "infinite number of paths"? No.
2026-11-06 10:45:17
0
l :
Markov chain?
2026-11-05 21:55:59
224
adriana :
Why is it not infinity since if there are an infinite amount of possibilities won’t that drag up the average to infinity
2026-11-06 05:46:45
5
Steven Madden :
Just guessing 4ish
2026-11-05 21:27:43
304
(づ￣ 𝟹￣)づ anish :
Hint: the answer is between 1 and 1 million
2026-11-05 21:35:16
745
Sh :
8.5? You can represent this as a 4 state Markov chain where for each step, you either advance or step away from the opposite corner.
2026-11-06 01:07:36
40
Caldeman14 :
funily enough you can't go from 1 side to the other in exactly 10 steps
2026-11-05 23:25:46
198
Q :
This is assuming the ant wants to get to the other side. It’s equally likely they just bounce between two points forever
2026-11-05 23:52:38
162
Jelly v20 :
Unclear: it wasnt stated you could go back
2026-11-06 00:59:04
51
Sid___ :
Monte carlo also works
2026-11-05 23:58:17
5
Hotbutter :
There’s definitely not an infinite amount of paths as you say.
2026-11-05 22:32:40
5
Oliver is a dumbass :
can the ant revisit points?
2026-11-05 23:27:15
15
Garbanzo :
I would much rather make a simulation and run it for millions of iterations
2026-11-05 23:10:04
16
Burgs_MR :
3.5
2026-11-05 21:45:37
3
NotHereForLong :
reminds me of Automata theory
2026-11-05 19:58:04
12
Shadow :
I did without node redundancy, so shortest 3, max 7, avg is 5
2026-11-06 06:39:24
0
Josh :
More of these man I need to unfry my brain from this app every now and then 🙏
2026-11-05 23:05:10
7
Shhhhhh :
You still need to convert the steps in the plan to steps the ant takes and they got six legs so don’t forget to account for that
2026-11-06 00:12:12
2
Zy👻 :
I got 10. For an even number of steps the ant is always on the 2nd node, which it has a 2/9 chance of reaching the end in the next 2 moves (Geom. dist). Skipping the first step and only counting odds, the mean is 2(9/2)+1 = 10.
2026-11-06 03:46:53
3
🤷 :
3 easy
2026-11-06 04:15:22
1
Nisse✌🏻 :
9 ish
2026-11-05 23:41:16
3
harman :
10
2026-11-05 23:28:48
1
Tommy Chan :
Enumerate breadth first search, for each path count the steps, then just take the average of them. Easy AF
2026-11-05 21:49:40
2
b4obao07 :
infinite
2026-11-06 05:21:16
1
Q10726 :
8
2026-11-05 23:12:46
1
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