@flat.earth.final.b: Replying to @forsure3331

FLAT EARTH FINAL BOSS
FLAT EARTH FINAL BOSS
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Region: GB
Monday 09 November 2026 11:59:16 GMT
2014
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shill.of.nasa
Agent Smith :
This doesn’t make the earth flat.
2026-11-09 18:55:45
2
thaiotis69
Thaiotis69 🇺🇸 :
earthquakes. lava. high tide low tide. can any of your flat earthers explain any of that
2026-11-10 00:21:21
0
flat.earth.final.b
FLAT EARTH FINAL BOSS :
@peterpanspants
2026-11-09 23:45:14
0
flat.earth.final.b
FLAT EARTH FINAL BOSS :
@am__ine16
2026-11-09 22:37:27
0
flat.earth.final.b
FLAT EARTH FINAL BOSS :
@dxxthly
2026-11-09 18:21:17
0
flat.earth.final.b
FLAT EARTH FINAL BOSS :
@jaybeeski5
2026-11-09 14:40:40
0
rodrigoantonioarm4
Rodrigo Antonio Armijo Moya :
flat earthers= Tik tok scientists😏😏😏😏
2026-11-09 13:02:09
2
chrncavngr
chrnc avngr :
great debunk of flat earth
2026-11-09 18:18:42
2
stevehv4
stevehv4 :
Sky Free is a really great channel over on YouTube I've been subscribed to them for years now and they do some excellent scientific experiments
2026-11-09 12:06:18
0
buckz94z28
Wade :
Want to calculate how much of an object Earth's curvature actually hides? Here's the formula: Hidden height = 0.667 × (d − 1.225√h)² d = distance in miles h = observer's eye height in feet Hidden height = feet This applies when the object is beyond the observer's horizon. Example: An object 20 miles away, viewed from 6 feet above water: Observer's horizon = 3 miles Hidden height ≈ 193 feet That means approximately 193 feet of the object's bottom is hidden by Earth's curvature, ignoring atmospheric refraction. The famous 8 inches per mile squared formula calculates curvature drop below a tangent line, NOT how much of an object is hidden. Observer height matters! 🌎
2026-11-09 18:00:50
0
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