@brainblastsat: This tricky SAT problem is actually easy #satprep #digitalsat #satstrategies #satmath #satreading

Giant Toilet :

This isn't math. It's just guessing.

P1NRK0 :

Or… u could just plug it into desmos (replace k with x)?

annas :

k = -2

tavaresh :

missed two imaginary solutions

KenzoLeFake :

Magooey3 :

you could just put k^2-k^3~12 in desmos. it takes like 10 seconds

:𝚙 :

how did -k³ become (1-k)?

logₐ(a)=1 :

Where are the other two solutions? We need to prove that this is the only solution

thodoris :

Horner?

BlueTome :

It has three solutions (one real and two complex)

cyfr0n_ :

k²(1-k)=12 three terms so no more than 3 solutions exist idk how to cobtinue

wiertarkaudarowa :

dweller41 :

Once you have -2, polynomial division and quadratic formula will give you the other two solutions: (3+-i√15)/2

GOLLY P :

missed some solutions…

mcwoocynle3 :

The key is 12=22+23

𝕾𝖆𝖎𝖓𝖙✦ :

I think it can be done like this 🙃

アルマット :

so you forgot about () when you set value of k² to -2

Abd Elkader Miled :

Since when we solve equations like this??

WhyEhmm :

how did k³ turn into (1 - k)?

JE$U$ €HR1$T2026 :

vieta× something long but smart✔️

Zephyro :

-2² is -4, you need () to make it (-2)² which is 4

soraya 𖣂 :

just take the k out. u get three answers of 0, and the two other numbers from factoring

Killua :

YOOO I THINK I GET HOW TO DO THIS so you take k² then you times it by 2 things that when added together gives k²-k³ and since k²×1 is k² and k²×(-k) is -k³ then the full equation is k²(1-k) and add them and you get k² plus k³!!!! but how is this usefull to know? i mean whats actually happening when you rewrite it like that?

ImYrMama :

You forgot 2 more solutions: \frac{3 + i\sqrt{15}}{2}, \frac{3 - i\sqrt{15}}{2}

ドソイクリオヌス 🇲🇳 :

ln(k²) - ln(k³) = ln(12) -ln(k) = ln(12) ln(k) = ln(1/12) k = 1/12 which surprisingly will deceive a lot of people